Answer:
The speed is constant.
Explanation:
The equation for a straight-line graph is
<em>y</em> = m<em>x</em> + b
where m and b are constants.
m is the <em>slope</em> of the line and b is the <em>y-intercept.
</em>
If we change the variables, the equation becomes
<em>d</em> = m<em>t</em> + b
![m = \frac{\Delta d}{\Delta t} = = \frac{\text{ distance}}{\text{time}} = \text{speed}](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7B%5CDelta%20d%7D%7B%5CDelta%20t%7D%20%3D%20%3D%20%5Cfrac%7B%5Ctext%7B%20distance%7D%7D%7B%5Ctext%7Btime%7D%7D%20%3D%20%5Ctext%7Bspeed%7D)
Since m is constant, so is the speed.
Acceleration means that while it's falling, its speed will increase by 9.8 m/s
every second. That's the acceleration of everything that falls near the Earth's
surface, no matter how heavy or light the object is.
In 0.67 seconds, then, the speed of the acorn increases from zero to
(0.67 x 9.8) = <u>6.57 m/s</u> .
This question is incomplete, the complete question is;
The area of the gold electrodes on the quartz crystal microbalance at the opening of Chapter 2 is 3.3 mm^2. One gold electrode is covered with DNA at a surface density of 1.2 pmol/cm2.
(a) How much mass of the nucleotide cytosine (C) is bound to the surface of the electrode when each bound DNA is elongated by one unit of C. The mass formula mass of the bound nucleotide is cytosine + deoxyribose + phosphate = C9H10N3O6P = 287.2 g/mol
Answer: mass of the nucleotide (c) bound is 11.37 g
Explanation:
Given that the area of gold electrodes = 3.3 mm^2
surface density of one gold electrode = 1.2 pmol/cm^2
that is to that in every 1 cm^2 of area, 1.2 pmol DNA is present
therefore
mass of nucleotide present in 3.3 mm^2 is;
= (1.2/100 * 3.3) pmol
= 0.0396 pmol
we were given that formula mass of the bound nucleotide = 287.2 g/mol
so
mass of the nucleotide (c) bound = ( 287.2 * 0.0396 )g
mass of the nucleotide (c) bound = 11.37 g
Answer:
What are the correct coefficients when this chemical equation is
balanced? *
P4 + 02 P2O5
<h2>1, 5, 2</h2>
Explanation:
For this reaction we have a combination reaction. Balancing Strategies: This combination reaction is a lot easier to balance and if you can get an even number of oxygen atoms on the reactants side of the equation.