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I am Lyosha [343]
3 years ago
6

43 milliliters of water weighs 43 g. what is the density of the water?

Chemistry
1 answer:
Anastaziya [24]3 years ago
4 0

Answer:

\rho =1g/mL

Explanation:

Hello,

In this case, since the density is defined as the ratio between the mass and the volume as shown below:

\rho =\frac{m}{V}

We can compute the density of water for the given 43 g that occupy the volume of 43 mL:

\rho =\frac{43g}{43mL}=1g/mL

Regards.

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Here, potassium is having an oxidation state of +1 called as K^{1+} cation and permanganate MnO_4^{1-} is an anion with oxidation state of -1. The charges are balanced. Thus, the compound formed will be, KMnO_4

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