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What properties of matter explain why the weight of an object on the moon is different than the weight of the same object on ear

algol13

Answer:

Gravity explains this.

Explanation:

Weights and mass are different terms .

Weight is defined as the force exerting on the surface due to the mass and gravity of acceleration.

$W=m*g$

Here mass is related to the density of the body. So as the density would be same mass woulnt vary.

Whereas the Gravity changes due to the property of the planet.

Gravity is different for different planets and hence moon and earth have two different values.

So the mass i.e density remains same on both planets but the g value always changes hence weight is different.

4 0

3 years ago

The human body is about 9.5% carbon atoms, with a small fraction of that carbon being radioactive carbon-14. Carbon dating is a

maw [93]

Answer:The age can be determined by utilizing carbon-14, a radioactive isotope of carbon.

Explanation:

8 0

2 years ago

A 2.0 M solution of LiF had 4.00 moles of LiF added to a solvent to make it.

kykrilka [37]

Answer:

2 L

Explanation:

From the question given above, the following data were obtained:

Molarity of LiF = 2 M

Mole of LiF = 4 moles

Volume =?

Molarity of a solution is simply defined as the mole per unit litre of the solution. Mathematically, it is expressed as:

Molarity = mole / Volume

With the above formula, we can obtain the volume of the solution as shown below:

Molarity of LiF = 2 M

Mole of LiF = 4 moles

Volume =?

Molarity = mole / Volume

2 = 4 / volume

Cross multiply

2 × volume = 4

Divide both side by 2

Volume = 4/2

Volume = 2 L

Therefore, the volume of the solution is 2 L.

3 0

2 years ago

Menthol, the substance we can smell in mentholated cough drops, is composed of C, H, and O. A 0.1005 g sample of menthol is comb

Bogdan [553]

Answer: The molecular formula for the menthol is $C_{10}H_{20}O$

Explanation:

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

$C_xH_yO_z+O_2\rightarrow CO_2+H_2O$

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of $CO_2=0.2829g$

Mass of $H_2O=0.1159g$

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 0.2829 g of carbon dioxide, $\frac{12}{44}\times 0.2829=0.077g$ of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 0.1159 g of water, $\frac{2}{18}\times 0.1159=0.0129g$ of hydrogen will be contained.

Mass of oxygen in the compound = (0.1005) - (0.077 + 0.0129) = 0.0106 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{0.077g}{12g/mole}=0.0064moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.0129g}{1g/mole}=0.0129moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{0.0106g}{16g/mole}=0.00066moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.00066 moles.

For Carbon = $\frac{0.0064}{0.00066}=9.69\approx 10$

For Hydrogen = $\frac{0.0129}{0.00064}=19.54\approx 20$

For Oxygen = $\frac{0.00066}{0.00066}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 10 : 20 : 1

Hence, the empirical formula for the given compound is $C_{10}H_{20}O_1=C_{10}H_{20}O$

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is :

$n=\frac{\text{molecular mass}}{\text{empirical mass}}$

We are given:

Mass of molecular formula = 156.27 g/mol

Mass of empirical formula = 156 g/mol

Putting values in above equation, we get:

$n=\frac{156.27g/mol}{156g/mol}=1$

Multiplying this valency by the subscript of every element of empirical formula, we get:

$C_{(1\times 10)}H_{(1\times 20)}O_{(1\times 1)}=C_{10}H_{20}O$

Thus, the molecular formula for the menthol is $C_{10}H_{20}O$

4 0

3 years ago

Read 2 more answers

How often do girls normally experience menstruation a.once every 30 days b. once every 29 c.once every 28 d.once every 27

kramer

Answer:

i think answer is a, every 30 days

5 0

3 years ago

Read 2 more answers