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borishaifa [10]

3 years ago

11

How many distinct arrangements can you make using the letters in the word experiment

1 answer:

Ratling [72]3 years ago

8 0

E x p e r i m e n t

Total number of letters = 10

Repeated letters = 3 e

Total arrangement from the 10 letters = 10!

Because of the repeated letters = 10! / 3!

   = (10 × 9 × 8 × 7× 6 × 5 × 4 × 3!) / 3!

   = 10 × 9 × 8 × 7× 6 × 5 × 4

   = 604800

604800 distinct arrangements.

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What is true about domain and range of the function?

zlopas [31]

Answer:

Another way to identify the domain and range of functions is by using graphs. Because the domain refers to the set of possible input values, the domain of a graph consists of all the input values shown on the x-axis. The range is the set of possible output values, which are shown on the y-axis.

7 0

3 years ago

Solving quadratic equations by factorization: 2x^2+5x-7=0 (step by step)

ch4aika [34]

Answer:

x = 1 ; x = -7/2

Step-by-step explanation:

$2x^2 + 5x - 7=0\\=> 2x^2 - 2x + 7x - 7=0\\=> 2x(x - 1) + 7(x - 1)=0\\=> (x - 1) (2x + 7)=0\\$

Here the sol. of x =

1) x - 1 = 0

=> x = 1

2) 2x + 7 = 0

=> 2x = -7

=> x = -7/2

5 0

4 years ago

Help this is due in 2 minutes

Alika [10]

Answer:

The percentage change each year is 2%

Step-by-step explanation:

Generally, we can have an exponential equation written as;

f(t) = I( 1 + r)^t

where f(t) is the value at a certain time

I is the initial value at t = 0

r is the growth rate

t is the time we are looking at

Thus, we have it that;

1.02 = 1 + r

r = 1.02 -1

r = 0.02

So, let us write 0.02 as a percentage

We have this as 2/100 which is the same as 2%

The percentage change each year is 2%

5 0

3 years ago

Which set is closed under subtractionWhich answer choice shows that the set of irrational numbers is not closed under addition

vovikov84 [41]

Answer:

(a) Set of rational numbers

(b) $\pi + (-\pi) = 0$

Step-by-step explanation:

Solving (a): Set that is closed under subtraction

The solution to this is rational numbers.

For a set of number to be closed under subtraction, the following condition must be true

$a -b = c$

Where

a, b, c are of the same set.

The above is only true for rational numbers.

e.g.

$1 - 2 = -1$

$5 - 5 = 0$

$\frac{1}{2} - \frac{1}{4} = \frac{1}{2}$

$4 - 2 = 2$

The operations and the result in the above samples are rational numbers.

Solving (b): Choice not close under addition[See attachment for options]

As stated in (a)

For a set of number to be closed under subtraction, the following condition must be true

$a -b = c$

Where

a, b, c are of the same set.

In the given options (a) to (d), only

$\pi + (-\pi) = 0$ is not close under addition because:

$\pi$ is irrational while $0$ is rational

<em>In other words, they belong to different set</em>

8 0

3 years ago

Neverminmd i dont need hekp

Alex777 [14]

Alright sounds good :)

7 0

4 years ago