Write reaction showing how each of the buffers would neutralize added naoh. hcho2 and nacho2

1 answer:

3 0

The acid-base neutralization reaction between formic acid (HCHO2) and sodium hydroxide (NaOH) is

HCHO2(aq) + NaOH(s) --> NaCHO2(aq) + H2O(l)

Formic acid is a weak acid. So, the salt formed here is a basic salt, NaCHO2 or Sodium Formate. A buffer solution is when the system contains either a weak acid and its conjugate strong base or a weak base and its conjugate strong acid. In this case, formic acid is the weak base, while sodium formate is the conjugate strong base. So, this is a buffer system. By definition, a buffer resists pH changes with small addition of either a base or an acid. So, when NaOH is added, it would produce more of sodium formate. As long as formic acid is not depleted, the buffer system would be stable.

You might be interested in

What is the mass of 2.70 ×10^22 molecules of NaOH (Molar mass = 40.0 g/mol)?

Viefleur [7K]

Data:
Molar Mass of NaOH = 40 g/mol

Solving: According to the Law Avogradro, we have in 1 mole of a substance, 6.02x10²³ atoms/mol or molecules

1 mol -------------------- 6.02*10²³ molecules
y mol -------------------- 2.70*10²² molecules

6.02*10²³y = 0.270*10²³
$y = \frac{0.270*\diagup\!\!\!\!\!\!10^{\diagup\!\!\!\!\!\!23}}{6.02*\diagup\!\!\!\!\!\!10^{\diagup\!\!\!\!\!\!23}}$
$\boxed{y \approx 0.04\:mol}$

Solving: Find the mass value now

40 g ----------------- 1 mol of NaOH
x g ------------- 0.04 mol of NaOH

$x = 40*0.04$
$\boxed{\boxed{x = 1.6\:g}}\end{array}}\qquad\quad\checkmark$

Answer:
The mass is 1.6 grams

6 0

2 years ago

Balance the following chemical equation by providing the correct coefficients.

sukhopar [10]

Answer:

2Na+2H2O→2NaOH+H2

Explanation:

I think this is it

7 0

2 years ago

20 POINTS!! please helps me with this word bank!! due today!! you can use a word more than once please help

Bogdan [553]