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nirvana33 [79]
3 years ago
12

A 0.4021-g sample of a purified organic acid was dissolved in water and titrated potentiometrically. A plot of the data revealed

a single end point after 19.31 mL of 0.1243 M had been introduced. Calculate the molecular mass of the acid.
Chemistry
1 answer:
Archy [21]3 years ago
6 0

Answer:

The molar mass of the acid is 167.5 g/mol

Explanation:

A 0.4021-g sample of a purified organic acid was dissolved in water and titrated potentiometrically. A plot of the data revealed a single end point after 19.31 mL of 0.1243 M NaOH had been introduced. Calculate the molecular mass of the acid.

Step 1: Data given

Mass of the sample of a purified organic acid = 0.4021 grams

Molarity = 0.1243 M

Volume needed to reach the end point = 19.1 mL = 0.01931 L

Step 2: Calculate the number of moles NaOH

Moles NaOH = molarity NaOH  * volume

Moles NaOH = 0.1243 M * 0.01931 L

Moles NaOH = 0.00240 moles

Step 3: Calculate moles of the acid

We'll need 0.00240 moles of acid to neutralize 0.00240 moles of NaOH ( it's a single end point)

Moles acid = 0.00240 moles

Step 4: Calculate molar mass of the acid

Molar mass = mass / moles

Molar mass = 0.4021 grams / 0.00240 moles

Molar mass = 167.5 g/mol

The molar mass of the acid is 167.5 g/mol

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Answer:

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Explanation:

What we know:

Balanced Equation: 3Ba+Al2(SO4)3 -->2Al+3BaSO4,

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Calculate the # of moles of Ba and Al2(SO4)3:

1g Ba/137.3 = 7.3 *10^-3 mol Ba

1.8g Al2(SO4)3/ 342 = 5.3 *10^-3 mol Al2(SO4)3

Find the limiting reactant:

Ba has a coefficient of 3 in the balanced equation, so we divide the # of moles of Ba by 3 to get... 7.3 *10^-3 mol Ba/3 = 2.43 *10^-3

Al2(SO4)3 has a coefficient of 1, so if we divide by 1, we get the same number of 5.3 *10^-3

2.43 *10^-3 is smaller than 5.3 *10^-3, therefore Ba is the limiting reactant.

finally, we just find the number of moles of Al

The ratio of Al to Ba is 2:3 so...

7.3 * 10^-3 * (2/3) = 5 *10^-3 mol Al

CONVERT TO GRAMS

5 *10^-3 mol Al  * 27 = 13.5 * 10^-2 g

<u>Hope that was helpful! </u>

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