Ions blowing outward from the sun (two words)

The____of an earthquake is the location where the rupture of an

exis [7]

Answer:

try hypocenter for the blank spot... hope this helps

Explanation:

7 0

3 years ago

C12H22O11 + 12O2 ---> 12CO2 + 11H2O

boyakko [2]

Answer:

Oxygen is the limiting reactant.

Explanation:

Based on the reaction:

C₁₂H₂₂O₁₁ + 12O₂ → 12CO₂ + 11H₂O

1 mole of sucrose reacts with 12 moles of oxygen to produce 12 moles of CO₂ and 11 moles of H₂O.

10.0g of sucrose (Molar mass: 342.3g /mol) are:

10.0g C₁₂H₂₂O₁₁ × (1mole / 342.3g) = 0.0292 moles of C₁₂H₂₂O₁₁

And moles of 10.0g of oxygen (Molar mass: 32g/mol) are:

10.0g O₂ × (1mole / 32g) = 0.3125 moles of O₂

For a complete reaction of 0.0292 moles of C₁₂H₂₂O₁₁ you need (knowing 12 moles of oxygen react per mole of sucrose):

0.0292 moles of C₁₂H₂₂O₁₁ × (12 moles O₂ / 1 mole C₁₂H₂₂O₁₁) = 0.3504 moles of O₂

As you have just 0.3125 moles of O₂, oxygen is the limiting reactant.

8 0

4 years ago

The prefab question someone help please !

lina2011 [118]

Answer: " 0.69 g / mL "

____________________________________________

Explanation:

______________________________________________

The "pre-lab question" given is:

_____________________________________________

"The volume of an unknown liquid is 15 ml, and the mass of the liquid and the graduated cylinder it is in is 55.2g. If the mass of the graduated cylinder is 44.8g , what is the density of the unknown liquid? " .

____________________________________________

Note: The volume of the unknown liquid is 15 mL ; regardless of whether or not the "unknown liquid" is in the graduated cylinder.

The density of the unknown liquid is measured in: "g / mL " ;

that is, "grams per mL" .

____________________________________________

Note: "D = m / V " ; that is; "Density = mass/ volume" ;

that is: ["Density = mass per 'unit volume' ]" .

____________________________________________

So; to find the density, "D" , of the "unknown liquid" ; we would have to find the "mass" of the "unknown liquid" by "subtracting" :

the "known mass of liquid when the liquid is not in the cylinder"; that is: " 44.8g" ; From:

the "known combined value of the: 'mass of the liquid PLUS the mass of the cylinder" ; that is: "55.2g" ;

→ " 55.2g - 44.8g = 10.4g " .

___________________________________________

So: " D = m / V " ; (55.2g - 44.8 g) / 15 mL " ;

= (55.2g - 44.8 g) / 15 mL " ;

= (10.4g) / 15mL ;

____________________________________________

Note that the "Density" = mass per "unit volume" ;

→ So: D = m / V ; in units of: " g / mL " (grams per millileter) ;

= (10.4g) / 15mL ;

= [ (10.4) / 15 } g/ mL ;

= 0.693333333333333.... g / mL ;

→ We round to "2 (two) significant figures" ;

→ since we have: "10.4 g / 15 mL " ;

and 15 mL is considered a measured/experimental value;

and: 10.4g is considered a measured/experimental value;

→ so, the least precise value; 15 mL (has only 2 (two) significant figures ;

compared to other value: 10.4g (which has 3 (three) significant figures;

→ so we shall round off to 2 (two) significant figures:

= 0.69 g / mL

____________________________________________

→ which is our answer: " 0.69 g / mL " .

____________________________________________

3 0

3 years ago

How many molecules in 11 grams of CO2?

yawa3891 [41]

Answer:

1095.62

Explanation:

5 0

3 years ago

Compare and contrast the atomic structures of helium and lithium at room temperature

kykrilka [37]

Answer:

How is it possible that helium, having 2 protons, and lithium, having 3 protons, are so different in terms of their physical properties? How come one is a gas at room temperature and the other is a solid metal?

Then why lithium and beryllium, the latter having 1 proton more than the former, are both metals and solids at room temperature?

Now if you remove neutrons from the nuclei of any element (except hydrogen), they form isotopes that have similar chemical properties and different physical properties, while still being an atom of the same element - therefore the protons, if I understand it correctly, are what determine whether an element is a gas or a solid at room temperature, and not the neutrons (or even electrons). Is this true?

The deeper question is that why do the properties of elements and their atoms change significantly - in some cases as with helium and lithium - just by having an additional proton in their nucleus, if the fundamental building blocks of protons (quarks) are identical for each proton? Then in the case of lithium and beryllium, why is the change in physical properties so subtle compared to the first case?

Edit

This question has already been asked before, however I am specifically interested in helium and lithium - why is one a gas and the other a solid metal at room temperature, having completely different chemical and physical properties? Is this a result of the electron shell configuration? Why does an extra proton, neutron and electron give rise to such a difference?

6 0

3 years ago