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Natali [406]
3 years ago
7

Ions blowing outward from the sun (two words)

Chemistry
1 answer:
IrinaVladis [17]3 years ago
4 0
I am pretty sure that it is Solar Wind

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describe the" fear appeal" and how it's used in public messaging. Give an example or create your own public health message using
Vsevolod [243]
A good example is cigarretes they try to scare you into not smoking by telling you all of the downsides of smoking like lung cancer and i guess that would be fear appeal 
7 0
2 years ago
Dissolving 5.28 g of an impure sample of calcium carbonate in hydrochloric acid produced 1.14 L of carbon dioxide at 20.0 °C and
swat32

Answer:

\%\ mass\ of\ CaCO_3=93.37\ \%

Explanation:

Given that:

Pressure = 791 mmHg

Temperature = 20.0°C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T = (20 + 273.15) K = 293.15 K  

T = 293.15 K  

Volume = 100 L

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 62.3637 L.mmHg/K.mol  

Applying the equation as:

791 mmHg × 1.14 L = n × 62.3637 L.mmHg/K.mol  × 293.15 K  

⇒n of CO_2 produced =  0.0493 moles

According to the reaction:-

CaCO_3 + 2 HCl\rightarrow CaCl_2 + H_2O + CO_2

1 mole of carbon dioxide is produced 1 mole of calcium carbonate reacts

0.0493 mole of carbon dioxide is produced 0.0493 mole of calcium carbonate reacts

Moles of calcium carbonate reacted = 0.0493 moles

Molar mass of CaCO_3 = 100.0869 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

0.0493\ mol= \frac{Mass}{100.0869\ g/mol}

Mass_{CaCO_3}=4.93\ g

Impure sample mass = 5.28 g

Percent mass is percentage by the mass of the compound present in the sample.

\%\ mass\ of\ CaCO_3=\frac{Mass_{CaCO_3}}{Total\ mass}\times 100

\%\ mass\ of\ CaCO_3=\frac{4.93}{5.28}\times 100

\%\ mass\ of\ CaCO_3=93.37\ \%

3 0
2 years ago
Below are the steps of the engineering process (not necessarily in order): 1) Know the background 2) Do the work 3) Make a plan
LuckyWell [14K]

Answer:

4 - 1 - 3 - 2 - 6 - 5

Explanation:

During an engineering process, first, we need to identify the problem, or the need because the process only will occur because of some need. Then, it's necessary to know as much as possible about the problem and the things that already exist or already were tested to solve it. Knowing the background will make the work easy.

After that, it's necessary to plan the things we'll do, knowing the costs, the time needed for activities, how many people will be necessary for each step, etc. It's really important to make a plan. Then, do the work, following the plan. Thus, the process must be tested. During the test of the results, some problems must be found, so it's time to evaluate and redesign the process, to solve these problems found.

3 0
3 years ago
Heat Transfer Lab
scoray [572]

Heat Transfer Lab

The following represents a lab set up for heat transfer. The cup on the left started with boiling water at 100 degrees C and the cup on the right has water at 20 degrees C. There is an aluminum bar between the two cups allowing heat to transfer from one cup into the other. The set up will be left alone for 20 minutes and temperatures of each cup of water will be recorded every minute for 20 minutes.

mag-aral ka

5 0
2 years ago
5)
Drupady [299]

What amount of heat absorbs 50 g of steel (ce = 0.115 cal / g. ° C) that

does its temperature vary by 25 ° C?

Answer:

143.75cal

Explanation:

Given parameters:

Mass of steel  = 50g

Specific heat capacity of the steel  = 0.115cal/g°C

Temperature  = 25°C

Unknown:

Amount of heat = ?

Solution:

The amount of heat to cause this temperature change is dependent on mass and specific heat capacity of the substance.

  Amount of heat  = m C (ΔT)

m is the mass

c is the specific heat capacity

ΔT is the temperature change

 Now insert the parameters and solve;

  Amount of heat  = 50 x 0.115 x 25

  Amount of heat  = 143.75cal

4 0
2 years ago
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