Mass of Magnesium bromide : 5.76 g
<h3>Further explanation</h3>
Complete question
<em>What mass of Magnesium bromide is formed when 1.00 g of magnesium reacts with 5.00 g of bromine?</em>
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Reaction
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mol Mg

mol Br₂

Limiting reactants : Br₂(smaller)
mol MgBr₂ = mol Br₂=0.0313
mass MgBr₂ :

Answer : The total mass of oxygen gas released in the reaction will be, 12.8 grams
Explanation :
Law of conservation of mass : It states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.
This also means that total mass on the reactant side must be equal to the total mass on the product side.
The balanced chemical reaction will be,

According to the law of conservation of mass,
Total mass of reactant side = Total mass of product side
Total mass of
= Total mass of 
or,
Total mass of
= Mass of
+ Mass of 
As we are given :
Total mass of
= 16.12 grams
The mass of
= 9.72 grams
So,
Total mass of
= Mass of
+ Mass of 


Therefore, the total mass of oxygen gas released in the reaction will be, 12.8 grams
The balanced chemical reaction is:
C3H8 + 5O2 = 3CO2 + 4H2O
We are given the amount of C3H8 to be used for the reaction. This will be the starting point for the calculations.
73.7 g C3H8 (1 mol C3H8 / 44.11 g C3H8) ( 5 mol O2 / 1 mol C3H8 ) ( 32 g O2 / 1 mol O2 ) = 267.3 g O2
N2 H2 ——> NH3
Add a 3 in front of H2 and a 2 in front of NH3
So the answer would be
N2 3H2 ——> 2NH3
H2O2 Is a chemical compound called hydrogen peroxide