Question

Find the 200th term of the sequence: 1, 5, 9, 13, ...

Answer 1

Answer:

797

Step-by-step explanation:

Note there is a common difference d between consecutive terms, that is

d = 5 - 1 = 9 - 5 = 13 - 9 = 4

This indicates the sequence is arithmetic with n th term

$a_{n}$ = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 1 and d = 4, thus

$a_{200}$ = 1 + (199 × 4) = 1 + 796 = 797

Answer 2

Answer:

797

Step-by-step explanation:

i put it into a explicit formula which is an=1+4(200-1). then i used order of operations to solve. so

200-1 = 199

1+4(199)

4 x 199= 796

1 + 796 = 797