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alexdok [17]
2 years ago
9

Please answer this for brainliest. Both of them please :)

Mathematics
1 answer:
zysi [14]2 years ago
3 0

Answer:

1. 24

2.  24/3 = 24 divided by 3

Step-by-step explanation:

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the sum of two numbers is 35 think of 2 numbers that make up 35 and then subtract them and see if they make 15 {no the answer is
JulijaS [17]
25 and 10, since 25+10=35, and 25-10=15
8 0
3 years ago
HELPP <br> Complete the ratio table.<br> 5 1<br> 30 6<br> 60 _<br> 75 _<br> 80 _
goldfiish [28.3K]

Answer:

12 27 32 it could be wrong though

5 0
2 years ago
100 points!!! i will award brainliest!! Lines AB, and CD are straight lines. Find x and y
Ket [755]

<O = 16 degrees   vertical angles are equal


<O + 4x+90 = 180   DC is a straight line

16 +4x +90 = 180

106 +4x = 180

4x =74

x =18.5


16 +90  +2y= 180   DC is a straight line

106+2y=180

2y = 74

y= 37

Answer : y=37

x=18.5

3 0
3 years ago
Read 2 more answers
Please help me with math thanks
Korvikt [17]
Given that a room is shaped like a golden rectangle, and the length is 29 ft with the ratio of  golden rectangle being (1+√5):2, thus the width of the room will be:
ratio of golden triangle=(length if the room)/(width of the room)
let the width be x
thus plugging the values in the expression we get:
29/x=(1+√5)/2
solving for x we get:
x/29=2/(1+√5)
thus
x=(29×2)/(1+√5)
answer is:
x=58/(1+√5)
or
 byrationalizing the denominator by multiplying both the numerator and the denominator by (1-√5)
58/(1+√5)×(1-√5)/(1-√5)
=[58(1-√5)]/1-5
=(58√5-58)/4
7 0
3 years ago
​john's commute time to work during the week follows the normal probability distribution with a mean time of 26.7 minutes and a
Angelina_Jolie [31]
To evaluate the probability that a randomly selected day will be between 28 and 34 minutes we proceed as follows:
P(28<x<34)
First we evaluate the z-score for the above values:
z=(x-σ)/μ
μ=26.7
σ=5.1

when:
x=28
z=(28-26.7)/5.1
z=0.26
P(z<0.26)=0.6026

when x=34
z=(34-26.7)/5.1
z=1.43
P(z<1.43)=0.9236
hence:
P(28<x<34)=0.9236-0.6026=0.321~32.1%

6 0
3 years ago
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