Answer:
x/2 + 21 = 36
First we get rid of constants to isolate the variable.
In order to do that we must do the inverse operation.
Inverse operation of addition is subtraction.
-21 -21(subtracting 21 from both sides, whatever we do to the left side we do it to the right side too)
x/2 = 15
inverse property of division is multiplication
x2 x2
X = 30
<span>First we calculate z using the formula:
z = (x - μ)/σ</span>
Where:
x = our variable, 10
μ = mean, 8
σ = standard dev, 2
Substituting known
values:<span>
z = (10 - 8)/2
z = 2/2
z = 1
Using the tables of
the normal distribution to find the p-value with z = 1
p = 0.8413
Since we want
"greater than 10”, we need to subtract the probability from 1
therefore
p* = 1 - 0.8413 = <span>0.1587</span></span>
Well an axis is like the whole line, so I would think its A, hope this helps.
This is what we already know:
![\left[\begin{array}{cccc} &YB&NB&total\\YF&45&[unknown]&146\\NF&[unknown]&[unknown]&[unknown]\\total&144&[unknown]&428\end{array}\right]](https://tex.z-dn.net/?f=%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D%20%26YB%26NB%26total%5C%5CYF%2645%26%5Bunknown%5D%26146%5C%5CNF%26%5Bunknown%5D%26%5Bunknown%5D%26%5Bunknown%5D%5C%5Ctotal%26144%26%5Bunknown%5D%26428%5Cend%7Barray%7D%5Cright%5D%20%20%20)
And using this information, we can fill the table out. Remember that everything must add up to the total in the column and row. The complete table looks like this:
![\left[\begin{array}{cccc} &YB&NB&total\\YF&45&101&146\\NF&99&183&282\\total&144&284&428\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D%20%26YB%26NB%26total%5C%5CYF%2645%26101%26146%5C%5CNF%2699%26183%26282%5C%5Ctotal%26144%26284%26428%5Cend%7Barray%7D%5Cright%5D%20)
Using the complete table, we see the fraction for students that only like baseball is 
and students who only like football is 
. All you need to do is add these fractions together to get your answer.
In short, 200 students only like one of the two sports.
