<u>Corrected Question</u>
Points X and Y are endpoints of a diameter of Circle W. Point Z is another point on the circle. Find the probability that
XZY is a right angle.
Answer:
Probability=1
Step-by-step explanation:
<u>Theorem</u>
- If an Inscribed angle intercepts a semicircle, the angle is a right angle.
Given that X and Y are endpoints of a diameter of Circle W and point Z is on the circle's circumference.
I have prepared a diagram which is attached.
Then,
XZY is an angle which intercepts a semicircle.
By the theorem above,
XZY is a right angle.
Therefore, the probability that
XZY is a right angle =1
Answer:
![= \frac{6}{55}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B6%7D%7B55%7D)
Step-by-step explanation:
The computation of experimental probability is shown below:-
The Number of king in a well shuffled deck consists 52 cards which is
= 4
The Number of ways of drawing consists of 4 king in 13 repetitions which is
= ![^{13}C_4](https://tex.z-dn.net/?f=%5E%7B13%7DC_4)
In 13 repetition, 2 kings are drawn by
way
Now,
![P(E) = \frac{^{13}C_2}{^{13}C_4} = \frac{13 !} {(13-2) ! } / \frac{13 !}{(13 - 4)! 4!}](https://tex.z-dn.net/?f=P%28E%29%20%3D%20%5Cfrac%7B%5E%7B13%7DC_2%7D%7B%5E%7B13%7DC_4%7D%20%3D%20%5Cfrac%7B13%20%21%7D%20%7B%2813-2%29%20%21%20%7D%20%2F%20%5Cfrac%7B13%20%21%7D%7B%2813%20-%204%29%21%204%21%7D)
![= \frac{13 !}{11 !\ 2 !} / \frac{13 !}{9 !\ 4 !}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B13%20%21%7D%7B11%20%21%5C%202%20%21%7D%20%2F%20%5Cfrac%7B13%20%21%7D%7B9%20%21%5C%204%20%21%7D)
![= \frac{9 !\ 4 !}{11 !\ 2!}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B9%20%21%5C%204%20%21%7D%7B11%20%21%5C%202%21%7D)
![= \frac{4\times 3}{11\times 10}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B4%5Ctimes%203%7D%7B11%5Ctimes%2010%7D)
![= \frac{6}{55}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B6%7D%7B55%7D)
Therefore for computing the experimental probability we simply applied the above formula.
Answer:
Its 8
Step-by-step explanation:
3x+10+2x=50
3x+2x=5x
5x+10=50
5x+10-10=50-10
5x=40
x=8
5x8=40
may be 28 am i write sir or mam
Area = perimeter + 132.
Let each side of the city be x miles long, then:-
x^2 = 4x + 132
x^2 - 4x - 132 = 0
x = [-(-4) +/- sqrt((-4)^2 - 4 * 1 *-132)] / 2
x = 13.66, -9.66 We ignore the negative
So the city has dimension of 13.66 * 13.66
13.7 * 13.7 to nearest 10th