What is the area of the two-dimensional cross section that is parallel to face ABC ?

One shelf will hold 45 pounds of boxes. If you have to store 270 pounds of boxes, how many shelves will you need?

arlik [135]

Hi!

We will solve this using ratios, like this:

1 shelf holds 45 pounds

x shelves hold 270 pounds

______________________

x = (270*1)/45

x = 270/45

x = 6

6 shelves will be needed to hold 270 pounds of boxes.

Hope this helps!

6 0

3 years ago

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What is the least number of acute angles of quadrilateral can have

Ira Lisetskai [31]

Two acute angles is the least amount.

7 0

3 years ago

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A map of New York has a scale of 1/2 inch : 5 miles. Cindy knows the

saveliy_v [14]

Answer:

8.5 inches

Step-by-step explanation:

1/2 in = 5 miles

? = 85 miles.

So you would do 85/5 to figure out how many times you have to multiply 5 to get to 85.

85/5= 17

So then you would multiply 17 by 1/2 to get the answer 8.5. So that would b 8.5 inches

7 0

3 years ago

What is the value of (Negative one-half)–4?

melamori03 [73]

Answer:it is 16

Step-by-step explanation:

3 0

3 years ago

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A random variable x follows a normal distribution with mean d and standard deviation o=2. It is known that x is less than 5 abou

Vaselesa [24]

Answer:

The mean of this distribution is approximately 3.96.

Step-by-step explanation:

Here's how to solve this problem using a normal distribution table.

Let $z$ be the

$\displaystyle z = \frac{x - \mu}{\sigma}$ .

In this question, $x = 5$ and $\sigma = 2$ . The equation becomes

$\displaystyle z = \frac{5 - \mu}{2}$ .

To solve for $\mu$ , the mean of this distribution, the only thing that needs to be found is the value of $z$ . Since

The problem stated that $P(X \le 5) = 69.85\% = 0.6985$ . Hence, $P(Z \le z) = 0.6985$ .

The problem is that the normal distribution tables list only the value of $P(0 \le Z \le z)$ for $z \ge 0$ . To estimate $z$ from $P(Z \le z) = 0.6985$ , it would be necessary to find the appropriate

Since $P(Z \le z) = 0.6985$ and is greater than $P(Z \le 0) = 0.50$ , $z > 0$ . As a result, $P(Z \le z)$ can be written as the sum of $P(Z < 0)$ and $P(0 \le Z \le z)$ . Besides, $P(Z < 0) = P(Z \le 0) = 0.50$ . As a result: