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4 years ago

describe why it might not be a good idea to use a key where each symbol stands for 1 in a picture graph

1 answer:

8 0

It is not a good idea to use a key in a picture graph because it will give you the answer, and you will not have to do as much work and you won't understand how you got that answer.

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Is 0.07 equal to 0.007

Ilya [14]

Answer:

< No

Step-by-step explanation:

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3 years ago

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Ex 1: Triangle RST is rotated 90 degrees counterclockwise about the origin, then reflected across the x-axis. Find the coordinat

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3 years ago

Mr. Benson built a play area for his children and an office for himself Explain how he can find the amount of carpet he needs to

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Answer:

250 ft sq in total

Step-by-step explanation:

This is the amount of carpet needed

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3 years ago

What is the common difference for this arithmetic sequence?

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Subtract a number from the next number.

39 - 45 = -6

Answer: B. -6

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3 years ago

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Three security cameras were mounted at the corners of a triangles parking lot. Camera 1 was 110 ft from camera 2, which was 137

Nata [24]

Answer:

<em>Camera 2nd has to cover the maximum angle, i.e. </em> $78.70^\circ$ .

Step-by-step explanation:

Please have a look at the triangular park represented as a triangle $\triangle ABC$ with sides

a = 110 ft

b = 158 ft

c = 137 ft

1st camera is located at point C, 2nd camera at point B and 3rd camera at point A respectively.

We can use law of cosines here, to find out the angles $\angle A, \angle B, \angle C$

As per Law of cosine:

$cos C = \dfrac{a^{2}+b^2-c^2 }{2ab}\\cos B = \dfrac{a^{2}+c^2-b^2 }{2ac}\\cos A = \dfrac{b^{2}+c^2-a^2 }{2bc}$

Putting the values of a,b and c to find out angles $\angle A, \angle B, \angle C$ .

$cos C = \dfrac{110^{2}+158^2-137^2 }{2\times 110 \times 158}\\\Rightarrow cos C = \dfrac{12100+24964-18769 }{24760}\\\Rightarrow cos C =0.526\\\Rightarrow C = 58.24^\circ$

$cos B = \dfrac{110^{2}+137^2-158^2 }{2\times 110 \times 137}\\\Rightarrow cos B = \dfrac{12100+18769 -24964}{30140}\\\Rightarrow cos B = \dfrac{5905}{30140}\\\Rightarrow cos B =0.196\\\Rightarrow B = 78.70^\circ$

$cos A = \dfrac{158^{2}+137^2-110^2 }{2\times 158 \times 137}\\\Rightarrow cos A = \dfrac{24964+18769-12100}{43292}\\\Rightarrow cos A = \dfrac{31633}{43292}\\\Rightarrow cos A = 0.731\\\Rightarrow A = 43.05^\circ$

<em>Camera 2nd has to cover the maximum angle</em>, i.e. $78.70^\circ$ .

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4 years ago