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Mkey [24]
3 years ago
14

x2 + 7x - 18 Select one of the factors of the quadratic expression. A) (x+2) B) (x+6) C) (x-2) D) (x-6)

Mathematics
2 answers:
lubasha [3.4K]3 years ago
5 0
The factors of this expression would be (x+9)(x-2). You have to find two numbers that are factors of -18 that add up to 7. These numbers would be 9 and -2:
(9)x(-2)= -18
and 9 + (-2)= 7
Your answer is C) (x-2).
sineoko [7]3 years ago
5 0

Answer:

The right answer is C) (x - 2).

Step-by-step explanation:

Given x² + 7x -18 , to find the correct factor you have to apply Baskhara´s equation

x = [-b ± √(b²- 4·a·c)]/2·a where a,b and c are the coeficietns of the quadratic equation, with a= 1, b= 7 and c= -18.

When you replace each term on the formula, you have

x= [-7 ± √(7² - 4·1·(-18)]/ 2·1 ⇒ x = [-7 ÷ √121]/2 ⇒ then you will find two solutions x1 and x2.

x1 = (-7 + 11)/2 ⇒ x1= 2

x2 = (-7 - 11)/2 ⇒x2=-9

Here you have the factors of the given equation.

So, x² + 7x -18 = (x-2) · (x +9).

Summarizing, the correct option is C) (x - 2)

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\displaystyle\bf\\2)\\A_{61}=a_1+(61-1)\times r=-113+60\times5=-113+300=187\\\\S_{61}=(-113)+(-108)+(-103)+...+(-8)+(-3)+2+7+12+...+187\\\\S_{61}=SA+SB\\\\SA=(-113)+(-108)+(-103)+...+(-8)+(-3)=-(3+8+103+108+113)\\\\n=\frac{113-8}{5}+1=\frac{105}{5}+1=21+1=22~terms\\SA=-\Big( \frac{n(113+3)}{2} \Big)=-\Big( \frac{22\times116}{2} \Big)=-11\times116 =-1276

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\displaystyle\bf\\SB=2+7+12+...+187\\\\n=\frac{187-2}{5}+1=\frac{185}{5}+1=37+1=38~terms\\\\SB=\frac{n(187+2)}{2}=\frac{38\times189}{2}=19\times189=3591\\\\S_{61}=SA+SB=-1276+3591=2315\\\\\boxed{\bf S_{61}=2315}    

 

 

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