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creativ13 [48]
3 years ago
9

Jessie spent $10 on 3 hair accessories. Which point represents this relationship?

Mathematics
2 answers:
vova2212 [387]3 years ago
5 0

Answer:

The point is given by (3,10)

Step-by-step explanation:

We are given that,

Jessie spent $10 on 3 hair accessories.

Let us assume,

<em>x-axis represents the number of accessories</em>

<em>y-axis represents the cost spent (in dollars).</em>

<h3>So, the point representing the situation will be of the form (x,y).</h3>

According to the question, we have,

Number of accessories, x = 3

Cost of the accessories, y = $10

<h3>Thus, the point is given by (3,10).</h3>
allsm [11]3 years ago
4 0
If dollars is the y-axis, the point is 3, 10
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Answer:

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Step-by-step explanation:

divide 6 and 2 by six to get 1 person

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8 0
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jolli1 [7]

Answer:

You input the equation they give you into the table to get an outcome. The Equation they gave you is x=y. simply, what ever X is, thats what y is. x=y. On the table it says that X is 3. If x is 3 then y is three because they are equal. if X is 7 then Y is 7. its the same throughout the whole table. To write it as an ordered pair you write (X,Y) if x is three y is three so the ordered pair would look like (3,3)

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3 years ago
A plane takes off from an airport and flies at a speed of 400km/h on a course of 120° for 2 hours. the plane then changes its co
butalik [34]

Answer:

Distance from the airport = 894.43 km

Step-by-step explanation:

Displacement and Velocity

The velocity of an object assumed as constant in time can be computed as

\displaystyle \vec{v}=\frac{\vec{x}}{t}

Where \vec x is the displacement. Both the velocity and displacement are vectors. The displacement can be computed from the above relation as

\displaystyle \vec{x}=\vec{v}.t

The plane goes at 400 Km/h on a course of 120° for 2 hours. We can compute the components of the velocity as

\displaystyle \vec{v_1}=

\displaystyle \vec{v_1}=\ km/h

The displacement of the plane in 2 hours is

\displaystyle \vec{x_1}=\vec{v_1}.t_1=.(2)

\displaystyle \vec{x_1}=km

Now the plane keeps the same speed but now its course is 210° for 1 hour. The components of the velocity are

\displaystyle \vec{v_2}=

\displaystyle \vec{v_2}=km/h

The displacement in 1 hour is

\displaystyle \vec{x_2}=\vec{v_2}.t_2=.(1)

\displaystyle \vec{x_2}=km

The total displacement is the vector sum of both

\displaystyle \vec{x_t}=\vec{x_1}+\vec{x_2}=+

\displaystyle \vec{x_t}=km

\displaystyle \vec{x_t}=

The distance from the airport is the module of the displacement:

\displaystyle |\vec{x_t}|=\sqrt{(-746.41)^2+492.82^2}

\displaystyle |\vec{x_t}|=894.43\ km

8 0
4 years ago
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Notice the tickmark on the angles, those angles are equal to each other.

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what the dickens does that mean?

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