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3 years ago

Can some one help me is that correct ?

Mathematics

2 answers:

deff fn [24]3 years ago

8 0

Answer:

First one would be y=2x (the cost of each ticket is 2 and x is the number of tickets that you are buying)

The second one is y=x+10 (each ticket is one and 10 is the one time set up fee)

Ilia_Sergeevich [38]3 years ago

4 0

Answer:

i think it is..

Step-by-step explanation:

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Suppose matrix D is the inverse of matrix C. Which of the following is equal to D?

mr Goodwill [35]

Answer: (A) CDD

if D=C^-1

then

C D D = (C C^-1) D = I D = D

(where I is the identity matrix)

6 0

3 years ago

Read 2 more answers

HELP ME ANYONE ANYONE PLEASEEEEE I BEG FOR LOVE OF JESUS

soldi70 [24.7K]

Answer:

b. -84

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtract Property of Equality

Algebra I

Terms/Coefficients

Step-by-step explanation:

Step 1: Define

$\displaystyle \frac{a}{-7} - 7 = 5$

Step 2: Solve for a

Addition Property of Equality: $\displaystyle \frac{a}{-7} - 7 + 7 = 5 + 7$
[Simplify] Add: $\displaystyle \frac{a}{-7}= 12$
Multiplication Property of Equality: $\displaystyle -7 \cdot \frac{a}{-7} = 12 \cdot -7$
[Simplify] Multiply: $\displaystyle a = -84$

Step 3: Check

Plug in a into the original equation to verify it's a solution.

Substitute in a: $\displaystyle \frac{-84}{-7} - 7 = 5$
[Frac] Divide: $\displaystyle 12 - 7 = 5$
Subtract: $\displaystyle 5 = 5$

Here we see that 5 does indeed equal 5.

∴ a = -84 is the solution to the equation.

7 0

3 years ago

44.69 rounded to the nearest tenth

Romashka-Z-Leto [24]

The answer would be 44.7 not 44.5

3 0

3 years ago

Suppose your family buys a "movie card" from a DVD

topjm [15]

Y = 3x + 25, because I’m assuming that that you start by renting 25 movies.

8 0

2 years ago

What is the simplest form of ^3 square root 27a^3b^7

Irina-Kira [14]

$\bf \sqrt[3]{27a^3b^7}\quad 
\begin{cases}
27=3\cdot 3\cdot 3\\
\qquad 3^3\\
b^7=b^{3+3+1}\\
\qquad b^3b^3b^1\\
\qquad (b^2)^3b^1
\end{cases}\implies \sqrt[3]{3^3a^3(b^2)^3b^1}
\\\\\\
3ab^2\sqrt[3]{b^1}\implies 3ab^2\sqrt[3]{b}$

4 0

3 years ago

Read 2 more answers

Can some one help me is that correct ?​

Can some one help me is that correct ?