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tino4ka555 [31]

3 years ago

9

24 students in a class took an algebra test. If 18 students passed the test, what percent do not pass? Question 7 options: A) 6%

B) 75% C) 18% D) 25%

2 answers:

Pani-rosa [81]3 years ago

8 0

D: 25%

Hope this helps:)

ruslelena [56]3 years ago

6 0

18/24 passed that reduces to 3/4

So 1/4 didn't pass.

D. 25% is the answer

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Find the greatest solution for x+y when x^2+y^2 = 7, x^3+y^3=10

damaskus [11]

Answer:

4

Step-by-step explanation:

set

$f(x,y)=x+y\\$

constrain:

$g(x,y)=x^2+y^2 = 7\\h(x,y)=x^3+y^3=10$

Partial derivatives:

$f_{x}=1\\f_{y} =1 \\g_{x}=2x \\g_{y}=2y\\h_{x}=3x^2 \\h_{y}=3y^2$

Lagrange multiplier:

$grad(f)=a*grad(g)+b*grad(h)\\$

$\left[\begin{array}{ccc}1\\1\end{array}\right]=a\left[\begin{array}{ccc}2x\\2y\end{array}\right]+b\left[\begin{array}{ccc}3x^2\\3y^2\end{array}\right]$

4 equations:

$1=2ax+3bx^2\\1=2ay+3by^2\\x^2+y^2=7\\x^3+y^3=10$

By solving:

$a=4/9\\b=-2/27\\x+y=4$

Second mathod:

Solve for x^2+y^2 = 7, x^3+y^3=10 first:

$x=\frac{1}{2} -\frac{\sqrt{13}}{2} \ or \ y=\frac{1}{2} +\frac{\sqrt{13}}{2} \\x=\frac{1}{2} +\frac{\sqrt{13}}{2} \ or \ y=\frac{1}{2} -\frac{\sqrt{13}}{2} \\x+y=-5\ or\ 1 \or\ 4$

The maximum is 4

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tresset_1 [31]

Answer:

$81.55

Step-by-step explanation:

$15+15%=15x1.15=$17.25

$23+10%=23x1.1=$27.50

$32+15%=32x1.15=$36.80

Total=$81.55

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H = 338m + 127m

H = 465m

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