The feeders in battling machine are represented in proportions and fractions.
- The equation that represents the problem is:
- The feeder can hold <em>30 baseballs</em>, when full
The given parameters are:
<em />
<em> ------ 1/6 full</em>
<em />
<em> --- baseballs added</em>
<em />
<em> ---- 2/3 full</em>
<em />
So, the equation that represents the problem is:
So, we have:
The number of baseballs it can hold is calculated as follows:
Multiply through by 6
Collect like terms
Divide through by 3
Hence, the feeder can hold 30 baseballs, when full
Read more about proportions and fractions at:
brainly.com/question/20337104
The answer should be 21 hope it helps
Find ing the common denominator would make it 10.
for 1/2 to get to 10 you have to multiply by 5
1/2x5= 5/10
then you have to convert 2/5 to get the denominator to be 10
so you multiply 2/5 by 2
2/5x2= 4/10
5/10 is greater than 4/10
1. 3x+9-9=18-9
3x=9
x=3
2. 4x-12=20
4x-12+12=20+12
4x=32
x=8
3. x+0-0
x=0
4. x/2-2+2=9+2
x/2=11
(2)(x/2)=11(2)
x=22
5. 12x-21=3
12x-21+21=3+21
12x=24
x=2
6. 3x-15=18
3x-15+15=18+15
3x=33
x=11
7. 3x-25=14
3x-25+25=14+25
x=13
8. 3x+16=22
3x+16-16=22-16
x=2
9. 2x-8=2
2x-8+8=2+8
2x=10
x=5
10. 9x-18=9
9x-18+18=9+18
9x=27
x=3
11. x+0=0
x=0
12. 9x-8=19
9x-8+8=19+8
9x=27
x=3
If you want to check my answers
use substitution method by using the x into for each equation.
