Pls ,pls,plssss help my

Suppose the roots of the polynomial $x^2 - mx + n$ are positive prime integers (not necessarily distinct). Given that $m < 20

Vsevolod [243]

Answer:

18 values for n are possible.

Step-by-step explanation:

Given the quadratic polynomial:

$x^2 - mx + n$

such that:

Roots are positive prime integers and

$m < 20$

To find:

How many possible values of $n$ are there ?

Solution:

First of all, let us have a look at the sum and product of a quadratic equation.

If the quadratic equation is:

$Ax^{2} +Bx+C$

and the roots are: $\alpha$ and $\beta$

Then sum of roots, $\alpha+\beta = -\frac{B}{A}$

Product of roots, $\alpha \beta = \frac{C}{A}$

Comparing the given equation with standard equation, we get:

A = 1, B = -m and C = n

Sum of roots, $\alpha+\beta = -\frac{-m}{1} = m$

Product of roots, $\alpha \beta = \frac{n}{1} = n$

We are given that $m$

$\alpha$ and $\beta$ are positive prime integers such that their sum is less than 20.

Let us have a look at some of the positive prime integers:

2, 3, 5, 7, 11, 13, 17, 23, 29, .....

Now, we have to choose two such prime integers from above list such that their sum is less than 20 and the roots can be repetitive as well.

So, possible combinations and possible value of $n (= \alpha \times \beta)$ are:

$1.\ 2, 2\Rightarrow n = 2\times 2 = 4\\2.\ 2, 3 \Rightarrow n = 6\\3.\ 2, 5 \Rightarrow n = 10\\4.\ 2, 7\Rightarrow n = 14\\5.\ 2, 11 \Rightarrow n = 22\\6.\ 2, 13 \Rightarrow n = 26\\7.\ 2, 17 \Rightarrow n = 34\\8.\ 3, 3\Rightarrow n = 3\times 3 = 9\\9.\ 3, 5 \Rightarrow n = 15\\10.\ 3, 7 \Rightarrow n = 21\\$

$11.\ 3, 11\Rightarrow n = 33\\12.\ 3, 13 \Rightarrow n = 39\\13.\ 5, 5 \Rightarrow n = 25\\14.\ 5, 7 \Rightarrow n = 35\\15.\ 5, 11 \Rightarrow n = 55\\16.\ 5, 13 \Rightarrow n = 65\\17.\ 7, 7 \Rightarrow n = 49\\18.\ 7, 11 \Rightarrow n = 77$

So,as shown above 18 values for n are possible.

3 0

3 years ago

a glass jar has 64 chocolate. mark, dave and ralph will share the chocolate in the ratio of 1:1:2, how many chocolates will each

tia_tia [17]

Step-by-step explanation:

64/(1+1+2)

= 64/4

= 16

1 : 1 : 2

mark = 1×16 = 16

dave = 1×16 = 16

ralph = 2×16 = 32

8 0

2 years ago

Read 2 more answers

Which decimal is equivalent to 10/3

Aneli [31]

3.3333333 repeating
Take 10 and divide it by 3

6 0

3 years ago

What is the counter example for 'if you do not eat beef then you're not vegetarian'

slamgirl [31]

Answer: If you're not vegetarian, then you do not eat beef.

Step-by-step explanation:

Dismiss the 'if' and 'then':

- you do not eat beef

- you're not vegetarian

Now, all you have to do is switch their places:

- you're not vegetarian

- you do not eat beef

Now add the 'if' and 'then' back:

If you're not vegetarian, then you do not eat beef.

4 0

3 years ago

Maria studied the traffic trends in India. She found that the number of cars on the road increases by 10% each year. If there we

lord [1]

Answer:

b. 8,800,000.

Step-by-step explanation:

In maria study the number of cars on the road increases by 10% each year.

Total number of cars in the first year =80 million cars.

We will add 10% of 80 million to 80 milion to enable us get the number of cars for the second year.

For year 2 we have;

10% of 80,000,000+80,000,000

$\frac{10}{100}*80,000,000+80,000,000$

8,000,000 + 80,000,000

88,000,000

number of cars in year 2 = 88 million

We will add 10% of 88 million to 88 milion to enable us get the number of cars for the third year.

$\frac{10}{100}*88,000,000+88,000,000$

8,800,000+88,000,000

96,800,000

the number of cars on the road in year 3 compared to year 2 will just be the increase which is in BOLD. That is 8,800,000

or simply subtract the number of cars in year 2 from that in year 3;

96,800,000-88,000,000 = 8,800,000

8 0

3 years ago

Read 2 more answers