Pls ,pls,plssss help my

A bike rental stand at the beach charges $5 to rent a bike in targit charges to every half hour it is rented if someone pays $17

denis23 [38]

Answer:

They would have the bike for 1.7 hours

Step-by-step explanation:

The bike is rented at a charge of $5 for every half an hour,this can be expressed as:

$5 per 0.5 hours, to calculate the time one will have the bike if they pay $17

The amount of paid=Standard Rate per 1/2 of an hour/Number of hours

where;

The amount paid=$17

Standard Rate per 1/2 an hour=$5/0.5

Number of hours

Replacing;

n=(17×0.5)/5=1.7 hours

5 0

3 years ago

What is U over 72=2 over 4

Mademuasel [1]

U/72 = 2/4

means u/72 = 0.5

therefore u = 72*0.5

which equals 36

8 0

4 years ago

Read 2 more answers

Use the elimination method to solve the system of equations. Choose the

MatroZZZ [7]

Answer:

C

Step-by-step explanation:

7x + 3y = 30 (equation 1)

-2x + 3y = 3 (equation 2)

9x = 27 (subtract the two equations to eliminate y)

x = 3 (divide by 9)

7 * 3 + 3y = 30 (Substitute x = 3 into equation 1, it doesn't matter which equation you substitute into)

21 + 3y = 30 (7 * 3 = 21)

3y = 9 (Subtract 21)

y = 3 (divide by 3)

Answer is (3, 3)

6 0

3 years ago

Read 2 more answers

75% of the 40 beverages in the vending machine are sports drinks. How many of the beverages are sports drinks?

GrogVix [38]

There are 30 sports drinks
40/100 = 0,4x75 = 30

4 0

3 years ago

Goofy's fast food center wishes to estimate the proportion of people in its city that will purchase its products. Suppose the tr

Westkost [7]

Answer:

The probability that the sample proportion will differ from the population proportion by greater than 0.03 is 0.0143.

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes n ≥ 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

$\mu_{\hat p}=p$

The standard deviation of this sampling distribution of sample proportion is:

$\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}$

The sample selected consists of n = 254 individuals. The sample is quite large, i.e. n = 254 > 30. So the central limit theorem can be applied to approximate the distribution of sample proportion of people in the city that will purchase the products of Goofy's fast food.

The mean is:

$\mu_{\hat p}=p=0.05$

And the standard deviation is:

$\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.05(1-0.05)}{254}}=0.0137$

Now, we need to compute the probability that the sample proportion will differ from the population proportion by greater than 0.03.

That is:

$\hat p-p>0.03\\\hat p -0.05>0.03\\\hat p>0.08$

Compute the value of $P(\hat p>0.08)$ as follows:

$P(\hat p>0.08)=P(\frac{\hat p-\mu_{\hat p}}{\sigma_{\hat p}}>\frac{0.08-0.05}{0.0137})$

$=P(Z>2.19)\\=1-P(Z$

*Use a z-tale for the probability.

Thus, the probability that the sample proportion will differ from the population proportion by greater than 0.03 is 0.0143.

8 0

3 years ago