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FrozenT [24]
3 years ago
8

8x+32=1/5(25x-15)-4x

Mathematics
1 answer:
xxMikexx [17]3 years ago
5 0

Answer:

x=-5

Step-by-step explanation:

8x+32=5x-3-4x

8x+32=x-3

8x+32-32=x-3-32

8x=x-35

8x-x=x-35-x

7x=-35

x=-5

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Which expression is equivalent to 10a + 6?
victus00 [196]
There are a number of expressions that are equivalent to 10a+6.
To find them, you simply have to list the multiples of both 10 and 6.
10- 10 20 30 40 50 60 70 80 90 100
6- 6 12 18 24 30 36 42 48 54 60.
Then, when you multiply the fraction by anything, whether this is 2, 3 or 10, you just have to do this to both parts. 
All of the following expressions are equivalent to 10a+6
20a+12, 30a+18, 40a+24, 50a+30, 60a+36, 70a+42, 80a+48, 90a+54, 100a+60

Or, if you're looking to simplfy, then you have to find a common multiple, which is 2. Therefore, 2 goes outside of the bracket, and you then have to divide 10 by 2 to find out what goes inside the brack. 10a/2= 5a. 6/2=3, therefore, in a bracket, it becomes 2(5a+3)

Hope this helps :) 

8 0
3 years ago
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Will an exponential function always, never, or sometimes exceed a polynomial function?
patriot [66]
At some point, the exponential function always exceeds a polynomial function.
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3 years ago
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Please help guys ♡♡♡♡♡♡​
Oksanka [162]

Answer:

I'm pretty sure the Y position of the eyes is 70.

If the Variable Y is equal to 70, and the Y variable is where the Y axis value goes. Then the Y position of the eyes is equal to the Y variable which is 70. I think that makes sense, but feel free to comment if it does not so that I can help you figure it out.

4 0
3 years ago
Find the missing value when given the modulus.
kolbaska11 [484]

Solving the complex number, we get the value of the missing value that is ‘a’ = -6

We  have been given the expression as

          |a – i| = √37          (1)

Which is an expression of complex number. The general expression of complex number is given as

    z = x + iy

 where x is the real part and iy is the imaginary part

To find the modulus value, the formula is given by,

  |z| = |x + iy|

   |z| = √[(real part)2 + (imaginary part)2]

 |z| = √(x2 + y2)

According to the question, |z| = √37         (2)

Equating equation (1) and (2), we get

√(a2 + 1) = √37

(a2 + 1) = 37

a2 = 37 – 1

a2 = 36

a = √36

a = ±6

Now value of a can be 6 or -6. We have been given that the modulus is in third quadrant.

Hence the value will be negative. Therefore, the missing value will be -6.

Learn more about complex number here : brainly.com/question/5564133

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It would pay with 3 loads
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