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FrozenT [24]
3 years ago
8

8x+32=1/5(25x-15)-4x

Mathematics
1 answer:
xxMikexx [17]3 years ago
5 0

Answer:

x=-5

Step-by-step explanation:

8x+32=5x-3-4x

8x+32=x-3

8x+32-32=x-3-32

8x=x-35

8x-x=x-35-x

7x=-35

x=-5

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April worked 1 1/2 times as long on her math project as did Carl. Debbie worked 1 1/4 times as long as Sonia. Richard worked 1 3
vlada-n [284]

Answer:

        Student                                                            Hours worked

             April.                                                                  7\frac{7}{8} \ hrs

        Debbie.                                                                   8\frac{1}{8}\ hrs

        Richard.                                                                   7\frac{19}{24}\ hrs

Step-by-step explanation:

Some data's were missing so we have attached the complete information in the attachment.

Given:

Number of Hours Carl worked on Math project = 5\frac{1}{4}\ hrs

5\frac{1}{4}\ hrs can be Rewritten as \frac{21}{4}\ hrs

Number of Hours Carl worked on Math project = \frac{21}{4}\ hrs

Number of Hours Sonia worked on Math project = 6\frac{1}{2}\ hrs

6\frac{1}{2}\ hrs can be rewritten as \frac{13}{2}\ hrs

Number of Hours Sonia worked on Math project = \frac{13}{2}\ hrs

Number of Hours Tony worked on Math project = 5\frac{2}{3}\ hrs

5\frac{2}{3}\ hrs can be rewritten as \frac{17}{3}\ hrs.

Number of Hours Tony worked on Math project = \frac{17}{3}\ hrs.

Now Given:

April worked 1\frac{1}{2} times as long on her math project as did Carl.

1\frac{1}{2}  can be Rewritten as \frac{3}{2}

Number of Hours April worked on math project = \frac{3}{2} \times Number of Hours Carl worked on Math project

Number of Hours April worked on math project = \frac{3}{2}\times \frac{21}{4} = \frac{63}{8}\ hrs \ \ Or \ \ 7\frac{7}{8} \ hrs

Also Given:

Debbie worked 1\frac{1}{4} times as long as Sonia.

1\frac{1}{4}  can be Rewritten as \frac{5}{4}.

Number of Hours Debbie worked on math project = \frac{5}{4} \times Number of Hours Sonia worked on Math project

Number of Hours Debbie worked on math project = \frac{5}{4}\times \frac{13}{2}= \frac{65}{8}\ hrs \ \ Or \ \ 8\frac{1}{8}\ hrs

Also Given:

Richard worked 1\frac{3}{8} times as long as tony.

1\frac{3}{8} can be Rewritten as \frac{11}{8}

Number of Hours Richard worked on math project = \frac{11}{8} \times Number of Hours Tony worked on Math project

Number of Hours Debbie worked on math project = \frac{11}{8}\times \frac{17}{3}= \frac{187}{24}\ hrs \ \ Or \ \ 7\frac{19}{24}\ hrs

Hence We will match each student with number of hours she worked.

        Student                                                            Hours worked

             April.                                                                  7\frac{7}{8} \ hrs

        Debbie.                                                                   8\frac{1}{8}\ hrs

        Richard.                                                                   7\frac{19}{24}\ hrs

5 0
3 years ago
Read 2 more answers
Which of the following are point-slope equations of the line going through (3, 6) and (1, -2)? 
Assoli18 [71]
Here, first we need to calculate the slope of the line, 
m = y2 - y1 / x2-x1
m = 6 + 2 / 3 -1
m = 8/ 2
m = 4

Now, Take first coordinate: y - 6 = 4 (x - 3)
Second coordinate: y + 2 = 4 (x - 1)

In short, Your Answers would be Option A & F

Hope this helps!
6 0
3 years ago
Give the discriminant of the equation 0 = −x2+6x−9<br>please answer
Brut [27]

Answer:

x = 3

Steps:

- ( {x}^{2}  - 6x + 9) = 0

-  {(x - 3)}^{2}  = 0

{(x - 3)}^{2}  = 0

x - 3 = 0

There you go!

8 0
3 years ago
Which system of linear inequalities is represented by the graph?  ax – 3y &gt; 6 and y &gt; 2x + 4 bx + 3y &gt; 6 and y &gt; 2x 
igor_vitrenko [27]

The <em><u>correct answer</u></em> is:

bx + 3y > 6 and y > 2x + 4

Explanation:

Looking at the second inequality, the y-intercept is 4 and the slope is 2.  This means the graph of the line crosses the y-axis at (0, 4) and the line goes up 2 and over 1.  Since it is greater than, this means the graph is shaded above it.  Comparing this to the graph, the line for the blue part crosses the y-axis at (0, 4) and goes up 2 and over 1.  The graph is also shaded above the line.

For the first inequality, bx+3y > 6, we want to isolate y.  To do this, we subtract bx from each side:

bx+3y-bx > 6-bx

3y > 6-bx

Divide both sides by 3:

3y/3 > 6/3 - bx/3

y > 2 - (b/3)x

This means the line for this will have a y-intercept of 2 and decrease 1 while going over 3.  The orange section does this.  Additionally, since it is greater than, the graph should be shaded above the line.  This one is, so this is the correct answer.

3 0
3 years ago
Read 2 more answers
In a bowl of fruit there are green grapes and black grapes in the ratio 3:4.If there are 24 green grapes how many black grapes a
xxMikexx [17]

Answer:

If there are 24 green grapes, then there would be 32 black grapes!

Step-by-step explanation:

First, identify what you know.

1) In a bowl of fruit, there are green grapes, and black grapes.

2) The ratio of green grapes to black grapes is 3:4

3) There are 24 green grapes

Simply divide 4 by 3!

4/3 = 1.3

24 x 1.3 = 32

Hope this helps! :)

5 0
3 years ago
Read 2 more answers
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