Answer:
The ration of the molar solubility is 165068.49.
Explanation:
The solubility reaction of the magnesium hydroxide in the pure water is as follows.

![[Mg^{2+}][OH^{-}]](https://tex.z-dn.net/?f=%5BMg%5E%7B2%2B%7D%5D%5BOH%5E%7B-%7D%5D)
Initial 0 0
Equili +S +2S
Final S 2S
![K_{sp}=[Mg^{2+}][OH^{-}]](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BMg%5E%7B2%2B%7D%5D%5BOH%5E%7B-%7D%5D)


Solubility of
in 0.180 M NaOH is a follows.

![[Mg^{2+}][OH^{-}]](https://tex.z-dn.net/?f=%5BMg%5E%7B2%2B%7D%5D%5BOH%5E%7B-%7D%5D)
Initial 0 0
Equili +S +2S
Final S 2S+0.180M
![K_{sp}=[Mg^{2+}][OH^{-}]](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BMg%5E%7B2%2B%7D%5D%5BOH%5E%7B-%7D%5D)



Therefore, The ration of the molar solubility is 165068.49.
Chlorine has that electron configuration
Noble Gas. Metals have 1 or 2 Valence Electrons. Halogens have 7 Valence Electrons. Semi-Metals can have different amounts.
I believe it is B... because all balance equation are supposed to follow the law of conservation of mass
Answer : Cadmium sulfide (CdS) precipitate is formed.
Explanation :
When the sodium sulfide,
is mixed with cadmium sulfate,
then cadmium sulfide precipitate and sodium sulfate,
is formed. The cadmium sulfide is insoluble in hot and cold water but sodium sulfate is soluble in water.
The balanced chemical reaction will be,

This reaction is an example of double displacement reaction in which the cation and anion of the two reactants exchange their places to give two new products.
This is a chemical reaction where the two clear solutions mixed to produce a bright yellow colored precipitate of cadmium sulfide.