We know that 
, where 
is density, 
is mass, and 
is volume.
Substitute in the values we know and solve:
The volume of the nitrous oxide gas is 1729.3 Liters
<h3>What is the number of moles of gas present in 3.40 kg of nitrous oxide?</h3>
The number of moles of gas present in 3.40 kg of nitrous oxide is determined from the formula below:
Numbers of moles = mass/molar mass
the mass of nitrous oxide = 3.40 kg or 3400 g
the molar mass of nitrous oxide = 44.013 g/mol
Moles of gas = 3400 / 44.013
Moles of gas = 77.25 moles
Using the ideal gas equation to determine the volume of the gas:
PV= nRT
V = nRT/P
where;
- V is the volume of gas
- n is the number of moles of gas
- R is molar Gas constant = 0.082 L.atm/mol/K
- T is the temperature of the gas
V = 77.25 * 0.082 * 273 / 1
The volume of the gas = 1729.3 Liters
Learn more about ideal gas equation at: brainly.com/question/20212888
#SPJ1
Answer:
1.50 moles
Balanced equation: 2Fe + 3Cl₂ --> 2FeCl₃
<u>find moles of iron:</u>
moles = mass/Mr
moles = 55.8/56
moles = 0.9964 moles
<u>use molar ratio:</u>
2Fe : 3Cl₂
2 : 3
moles of Cl₂ = (0.9964/2)*3 = 1.50 moles
Explanation: Saponification reaction is a reaction in which hydrolysis of fats takes place under basic conditions giving glycerol and a salt of corresponding fatty acid.
We are given a Fatty acid called as Trimyristin.
Its reaction with KOH leads to the formation of soap and is given by the equation:
The condensed structural formula for the equation is given in the image attached.
