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prisoha [69]
4 years ago
8

Divisible by 3?

Mathematics
1 answer:
masya89 [10]4 years ago
4 0
The third one is divisible by 3; and you can figure that out quickly by adding up the individual numbers in each number and seeing if it is divisible by 3.  
Example: 8+5+0+1+9+4+5+7 = 39    39/3 = 13
3+2+8+3+2+9+8+8 = 43    43/3 = 14 1/3

Only works like that when dividing by 3 though
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Kaylis [27]

Answer:

0.77

Step-by-step explanation:

I just guessed

3 0
4 years ago
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4) From a graphed linear line, how do you find the<br> Slope:<br> Y-intercept:
Ad libitum [116K]

Rise over Run

Put the amount you go up or down on the Y-axis over how much you go right or the x-axis

the Y-intercept is found simply by looking where the graph crosses the y, if the equation is written instead of graphed, graph it using a graphing calculator, then use the information I gave you previously : )

8 0
3 years ago
Determine whether it is a function or not. Give reason for your answer.
tekilochka [14]

Hey there!!

The given set is a function

( x , y ) - this is the form in which we write co-ordinates

In order to be a function , at least x values shall repeat.

Noted down all the x values

2 , -1, 4 , -2

None of the values is repeating.

Hence, the given data is a function

Hope my answer helps!

8 0
3 years ago
Which linear function represents a slope of 1?
algol13
Yes yes woeoshdenenejdjdjdjejejrjrrjekekekekekeek 30
8 0
3 years ago
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What is the area of the shaded region in the figure below ? Leave answer in terms of pi and in simplest radical form
ser-zykov [4K]

Answer:

Step-by-step explanation:

That shaded area is called a segment. To find the area of a segment within a circle, you first have to find the area of the pizza-shaped portion (called the sector), then subtract from it the area of the triangle (the sector without the shaded area forms a triangle as you can see). This difference will be the area of the segment.

The formula for the area of a sector of a circle is:

A_s=\frac{\theta}{360}*\pi r^2 where our theta is the central angle of the circle (60 degrees) and r is the radius (the square root of 3).

Filling in:

A_s=\frac{60}{360}*\pi (\sqrt{3})^2 which simplifies a bit to

A_s=\frac{1}{6}*\pi(3) which simplifies a bit further to

A_s=\frac{1}{2}\pi which of course is the same as

A_s=\frac{\pi}{2}

Now for tricky part...the area of the triangle.

We see that the central angle is 60 degrees. We also know, by the definition of a radius of a circle, that 2 of the sides of the triangle (formed by 2 radii of the circle) measure √3. If we pull that triangle out and set it to the side to work on it with the central angle at the top, we have an equilateral triangle. This is because of the Isosceles Triangle Theorem that says that if 2 sides of a triangle are congruent then the angles opposite those sides are also congruent. If the vertex angle (the angle at the top) is 60, then by the Triangle Angle-Sum theorem,

180 - 60 = 120, AND since the 2 other angles in the triangle are congruent by the Isosceles Triangle Theorem, they have to split that 120 evenly in order to be congruent. 120 / 2 = 60. This is a 60-60-60 triangle.

If we take that extracted equilateral triangle and split it straight down the middle from the vertex angle, we get a right triangle with the vertex angle half of what it was. It was 60, now it's 30. The base angles are now 90 and 60. The hypotenuse of this right triangle is the same as the radius of the circle, and the base of this right triangle is \frac{\sqrt{3} }{2}. Remember that when we split that 60-60-60 triangle down the center we split the vertex angle in half but we also split the base in half.

Using Pythagorean's Theorem we can find the height of the triangle to fill in the area formula for a triangle which is

A=\frac{1}{2}bh. There are other triangle area formulas but this is the only one that gives us the correct notation of the area so it matches one of your choices.

Finding the height value using Pythagorean's Theorem:

(\sqrt{3})^2=h^2+(\frac{\sqrt{3} }{2})^2 which simplifies to

3=h^2+\frac{3}{4} and

3-\frac{3}{4}=h^2 and

\frac{12}{4} -\frac{3}{4} =h^2 and

\frac{9}{4} =h^2

Taking the square root of both the 9 and the 4 (which are both perfect squares, thankfully!), we get that the height is 3/2. Now we can finally fill in the area formula for the triangle!

A=\frac{1}{2}(\sqrt{3})(\frac{3}{2}) which simplifies to

A=\frac{3\sqrt{3} }{4}

Therefore, the area in terms of pi for that little segment is

A_{seg}=\frac{\pi}{2}-\frac{3\sqrt{3} }{4}, choice A.

8 0
3 years ago
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