Answer:
Step-by-step explanation:
If Quan had 15 and Kaden had 3 times as much, then Kaden had 15(3) = 45. If he spent 10 then he had 35 left. The amount of money Quan had after his mom gave him some was 4/5 the amount of Kaden's 35 (let x = the amount of money Quan has after his mom gives him some):
35 divides by the 5 in the denominator 7 times, and 7 times 4 is 28. That's how you get your 28 in part a.
For part b., he started with 15 and ended with 28, so his mom gave him 28-15=13. That's how you get the 13.
La ecuación que nos dice cuantas niñas hay en el colegio es:
A = x - c*m
¿Como encontrar una expresión para la cantidad de niñas?
Sabemos que hay un total de x estudiantes, definimos las variables:
- A = cantidad total de niñas
- B = cantidad total de niños.
Entonces tenemos A + B = x
Tambien sabemos que los estudiantes estan divididos en c cursos, de tal forma que hay m niños por curso.
Entonces c por m es igual a la cantidad total de niños:
c*m = B
Reemplazando esto en la ecuación de arriba podemos obtener:
A + c*m = x
A = x - c*m
Esta es la ecuación que nos da el numero total de niñas en el colegio.
Sí quieres aprender más sobre ecuaciones, puedes leer:
brainly.com/question/18168483
Answer:
simplify = 220x^2+2f−6x−14
factor = 2(110x^2+f−3x−7)
Answer:
x = 7
x = -5
Step-by-step explanation:
Given
x² - 2x - 35 = 0
Consider the factors of the constant term (- 35) which sum to give the coefficient of the x- term (- 2)
The factors are - 7 and + 5, since
- 7 × 5 = - 35 and - 7 + 5 = - 2, thus
(x - 7)(x + 5) = 0
Equate each factor to zero and solve for x
x + 5 = 0 ⇒ x = - 5
x - 7 = 0 ⇒ x = 7
Answer:
H0 : μYellow = μGreen
H1 : μYellow < μGreen
Step-by-step explanation:
Let :
Yellow paper = μYellow
Green paper = μGreen
To test the hypothesis :
The null hypothesis is will state that there is no difference in mean of anxiety scores obtained for test taken of yellow and green papers
H0 : μYellow = μGreen.
The alternative hypothesis is the opposite of the null and it is to the left, where we want to test if the anxiety score is lower when take on a yellow paper
H1 : μYellow < μGreen
