<span> I am assuming you want to prove:
csc(x)/[1 - cos(x)] = [1 + cos(x)]/sin^3(x).
</span>
<span>If we multiply the LHS by [1 + cos(x)]/[1 + cos(x)], we get:
LHS = csc(x)/[1 - cos(x)]
= {csc(x)[1 + cos(x)]/{[1 + cos(x)][1 - cos(x)]}
= {csc(x)[1 + cos(x)]}/[1 - cos^2(x)], via difference of squares
= {csc(x)[1 + cos(x)]}/sin^2(x), since sin^2(x) = 1 - cos^2(x).
</span>
<span>Then, since csc(x) = 1/sin(x):
LHS = {csc(x)[1 + cos(x)]}/sin^2(x)
= {[1 + cos(x)]/sin(x)}/sin^2(x)
= [1 + cos(x)]/sin^3(x)
= RHS.
</span>
<span>I hope this helps! </span>
Answer:
Step-by-step explanation:
mid point formula = (x1+x2/2 , y1+y2/2)
hence putt the values we get,
mid point = ( -1+3/2 , 7-2/2)
= (1 , 2.5)
Step-by-step explanation:
1 * (-5) = -5 a = -5
6 + (-5) = 1 b = 1
1 * (-5 ) = -5 c = -5
-7 + -5 = -12 d = -12
Answer:
19,600
Step-by-step explanation:
0-49=50 numbers
n=50
r=3
C(n,r)=n!/(r!(n-r)!)
=50!/(47!)(3!)
C(n,r)=C(50,3)
=50!/(3!(50−3)!)
= 19600
Answer:
Step-by-step explanation:
Subtract x from both sides.
Square both sides.
Subtract x²-6x+9 from both sides.
Factor left side of the equation.
Set factors equal to 0.
Check if the solutions are extraneous or not.
Plug x as 2.
x = 2 works in the equation.
Plug x as 6.
x = 6 does not work in the equation.
