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andrew11 [14]
3 years ago
15

Estimate the total weight of two boxes that weigh 9.4 and 62.6 pounds using rounding and compatible numbers. which estimate is c

loser to the actual total weight? why?
Mathematics
1 answer:
Anit [1.1K]3 years ago
8 0
With rounding:
4 is less than 5 so we round it down to whole number:
9.4\approx9

6 is more than 5 so we round it up to whole number:
62.6\approx63

Now we have to add rounded numbers
63+9=72

Without rounding:
62.6+9.4 to make it more visible I will write it differently:

62+9+0.6+0.4 is equal to 62.6+9.4

we can see that 0.6+0.4 is equal to 1

so:
62+9+1=72

<span>As you see in this example those equations are equal so it doesn't matter if you take rounded numbers or not, it may be different in case like 62.4+9.4  ( 0.4 is just an example it could be any other number between 0-4 ) because in this case it will be equal 71 and another example 62.5+9.5 (in this case 0.5 is just an example, it can be any other number between 5-9 :) ) and here, answer for this equation is 73.</span>

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tatiyna

Answer:

1 and 3

Step-by-step explanation:

Part a: 1 and 3

part b: x = −22

<u><em>Please mark as brainliest </em></u>

Have a great day, be safe and healthy  

Thank u  

XD

8 0
3 years ago
Read 2 more answers
solve for each please i really need help if u want to help me with my test and i get an a or a b i will give u 500 dollars
Len [333]

Answer:

The relation is not a function

The domain is {1, 2, 3}

The range is {3, 4, 5}

Step-by-step explanation:

A relation of a set of ordered pairs x and y is a function if

  • Every x has only one value of y
  • x appears once in ordered pairs

<u><em>Examples:</em></u>

  • The relation {(1, 2), (-2, 3), (4, 5)} is a function because every x has only one value of y (x = 1 has y = 2, x = -2 has y = 3, x = 4 has y = 5)
  • The relation {(1, 2), (-2, 3), (1, 5)} is not a function because one x has two values of y (x = 1 has values of y = 2 and 5)
  • The domain is the set of values of x
  • The range is the set of values of y

Let us solve the question

∵ The relation = {(1, 3), (2, 3), (3, 4), (2, 5)}

∵ x = 1 has y = 3

∵ x = 2 has y = 3

∵ x = 3 has y = 4

∵ x = 2 has y = 5

→ One x appears twice in the ordered pairs

∵ x = 2 has y = 3 and 5

∴ The relation is not a function because one x has two values of y

∵ The domain is the set of values of x

∴ The domain = {1, 2, 3}

∵ The range is the set of values of y

∴ The range = {3, 4, 5}

3 0
2 years ago
Find the slope of the line -3x+5y=30
Dmitriy789 [7]
-3x+5y=30
+3x+5y=30
5y=3x+30
divide 5 by everything
answer: y=3/5x+6
4 0
3 years ago
How many three letter permutations can be formed from the first five letters of the alphabet?
Vsevolod [243]

Answer:

There are 60 permutations that can be formed from the first five letters of the alphabet.

Step-by-step explanation:

The number of three letter permutations that can be formed from the first five letters of the alphabet is 5P_{3}.

5P_{3} =\frac{5!}{(5-3)!}

=\frac{5!}{2!}

= 60

Hence, there are 60 permutations that can be formed from the first five letters of the alphabet.

6 0
3 years ago
Read 2 more answers
Part B: Solve 2a − 5d = 30 for d. Show your work. (6 points)
stich3 [128]
<span>Given Equation: 2a − 5d = 30 

Solution:

2a - 5d = 30

-5d = 30 -2a

d = ( 30 - 2a )/ (-5)

  =  -6 + (2a/5) 

  = (2a/5) - 6

I hope this helps</span>
3 0
3 years ago
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