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Leona [35]
4 years ago
13

Write a molecular equation for the precipitation reaction that occurs (if any) when the following solutions are mixed. If no rea

ction occurs, write NOREACTION.
sodium chloride and lead (II) acetate

potassium sulfate and strontium iodide

chromium (III) nitrate and sodium phosphate
Chemistry
2 answers:
Marrrta [24]4 years ago
8 0

sodium chloride and lead (II) acetate
potassium sulfate and strontium iodide
chromium (III) nitrate and sodium phosphate

1.       2NaCl + Pb(CH3COO)2 → 2NaCH3COO + PbCl2

2.       K2SO4 + SrI2 → KI + SrSO4

3.       Cr(NO3)3 + Na3PO4 →CrPO4 + NaNO3

TEA [102]4 years ago
7 0

<u>Answer:</u> All the reactions are precipitation reactions.

<u>Explanation:</u>

Precipitation reaction is defined as the reaction in which an insoluble salt is formed when two solutions are mixed containing soluble substances. The insoluble salt settles down at the bottom of the reaction mixture.

For the given options:

<u>Option 1:</u> Sodium chloride and lead (II) acetate

The chemical equation follows:

NaCl(aq.)+Pb(CH_3COO)_2(aq.)\rightarrow 2CH_3COONa(aq.)+PbCl_2(s)

As, lead (II) chloride is forming as a solid product. It is considered as a precipitation reaction.

<u>Option 2:</u> Potassium sulfate and strontium iodide

The chemical equation follows:

K_2SO_4(aq.)+SrI_2(aq.)\rightarrow 2KI(aq.)+SrSO_4(s)

As, strontium sulfate is forming as a solid product. It is considered as a precipitation reaction.

<u>Option 3:</u> Chromium (III) nitrate and sodium phosphate

The chemical equation follows:

Cr(NO_3)_3(aq.)+Na_3PO_4(aq.)\rightarrow 3NaNO_3(aq.)+CrPO_4(s)

As, chromium (III) phosphate is forming as a solid product. It is considered as a precipitation reaction.

Hence, all the reactions are precipitation reactions.

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A 5.0 balloon containing nitrogen gas is cooled from 25 degrees to 5°C. What is the final volume of the balloon?
mylen [45]

Answer:

5.4

Explanation:

V1=5.0

T1=25+ 273=298

V2= z(unknown)

T2=5+273=278

V1/T1 =V2/T2

V2=V1T2/T1

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<span>To find the mass of 3.00 moles of magnesium chloride (MgCl2), first record the atomic mass of magnesium (Mg) and chloride (Cl), which are both listed on the periodic table as follows: Mg=24 g/mole Cl=38 g/mole Now, double the Cl mass since there are 2 Cl moles in MgCl2 and then add it to the Mg mass like so: (38 g/mole*2 moles)+24 g/mole=100 g/mole Finally, to calculate the mass of 3.00 moles of MgCl2, convert the combined atomic mass to grams as follows: 3.00 moles * 100 g/mole = 300 g</span>
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