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Leona [35]
4 years ago
13

Write a molecular equation for the precipitation reaction that occurs (if any) when the following solutions are mixed. If no rea

ction occurs, write NOREACTION.
sodium chloride and lead (II) acetate

potassium sulfate and strontium iodide

chromium (III) nitrate and sodium phosphate
Chemistry
2 answers:
Marrrta [24]4 years ago
8 0

sodium chloride and lead (II) acetate
potassium sulfate and strontium iodide
chromium (III) nitrate and sodium phosphate

1.       2NaCl + Pb(CH3COO)2 → 2NaCH3COO + PbCl2

2.       K2SO4 + SrI2 → KI + SrSO4

3.       Cr(NO3)3 + Na3PO4 →CrPO4 + NaNO3

TEA [102]4 years ago
7 0

<u>Answer:</u> All the reactions are precipitation reactions.

<u>Explanation:</u>

Precipitation reaction is defined as the reaction in which an insoluble salt is formed when two solutions are mixed containing soluble substances. The insoluble salt settles down at the bottom of the reaction mixture.

For the given options:

<u>Option 1:</u> Sodium chloride and lead (II) acetate

The chemical equation follows:

NaCl(aq.)+Pb(CH_3COO)_2(aq.)\rightarrow 2CH_3COONa(aq.)+PbCl_2(s)

As, lead (II) chloride is forming as a solid product. It is considered as a precipitation reaction.

<u>Option 2:</u> Potassium sulfate and strontium iodide

The chemical equation follows:

K_2SO_4(aq.)+SrI_2(aq.)\rightarrow 2KI(aq.)+SrSO_4(s)

As, strontium sulfate is forming as a solid product. It is considered as a precipitation reaction.

<u>Option 3:</u> Chromium (III) nitrate and sodium phosphate

The chemical equation follows:

Cr(NO_3)_3(aq.)+Na_3PO_4(aq.)\rightarrow 3NaNO_3(aq.)+CrPO_4(s)

As, chromium (III) phosphate is forming as a solid product. It is considered as a precipitation reaction.

Hence, all the reactions are precipitation reactions.

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3 0
3 years ago
Given the following balanced equation, determine the rate of reaction with respect to [Cl2]. If the rate of disappearance of Cl2
s2008m [1.1K]

Answer : The rate of formation of NOCl is, 8.48\times 10^{-2}M/s

Explanation : Given,

Rate of disappearance of Cl_2 = 4.24\times 10^{-2}M/s

The given rate of reaction is,

2NO(g)+Cl_2(g)\rightarrow 2NOCl

The expression for rate of reaction :

\text{Rate of disappearance}=-\frac{1}{2}\frac{d[NO]}{dt}=-\frac{d[Cl_2]}{dt}

\text{Rate of formation}=\frac{1}{2}\frac{d[NOCl]}{dt}

From this we conclude that,

\frac{1}{2}\frac{d[NOCl]}{dt}=-\frac{d[Cl_2]}{dt}

\frac{1}{2}\frac{d[NOCl]}{dt}=-\frac{d[Cl_2]}{dt}

\frac{d[NOCl]}{dt}=2\times \frac{d[Cl_2]}{dt}

Now put the value of rate of disappearance of Cl_2, we get:

\frac{d[NOCl]}{dt}=2\times (4.24\times 10^{-2}M/s)=8.48\times 10^{-2}M/s

Therefore, the rate of formation of NOCl is, 8.48\times 10^{-2}M/s

7 0
3 years ago
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