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Monica [59]
3 years ago
5

Drag the tiles to the correct locations. Each tile can be used more than once, but not all tiles will be used. One or more locat

ions will remain
empty.

Nitrosyl fluoride has the chemical formula NOF. Nitrogen has five valence electrons, oxygen has six, and fluorine has seven. Complete the Lewis

structure for this covalent compound,

F

N

=

=

=

Reset

Next

Chemistry
2 answers:
Nata [24]3 years ago
8 0

Answer:

Answer is on the foto.

Explanation:

Complete Lewis formula is on picture 2

Svetradugi [14.3K]3 years ago
4 0

Answer :  The Lewis structure of AsH_3 shows 1 non-bonding electron pair on as.

Explanation :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

The given molecule is, NOF

As we know that nitrogen has '5' valence electrons, oxygen has '6' valence electrons and fluorine has '7' valence electron.

Therefore, the total number of valence electrons in NOF = 5 + 6 + 7 = 18

According to Lewis-dot structure, there are 6 number of bonding electrons and 12 number of non-bonding electrons.

The Lewis-dot structure of NOF is shown below.

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Alona [7]
From the periodic table:
molecular mass of carbon = 12 grams
molecular mass of fluorine = 18.99 grams
molecular mass of chlorine = 35.5 grams
Therefore:
one mole of CF2Cl2 = 12 + 2(18.99) + 2(35.5) = 120.98 grams
Therefore, we can use cross multiplication to find the number of moles in 79.34 grams as follows:
mass = (79.34 x 1) / 120.98 = 0.6558 moles

Now, one mole contains 6.022 x 10^23 molecules, therefore:
number of molecules in 0.65548 moles = 0.6558 x 6.022 x 10^23
                                                              = 3.949 x 10^23 molecules
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3 years ago
Find the quantinum numbers n,m,l,s for the last of potassium layer pleasee help explain correctly all
Fantom [35]

Answer:

Quantum numbers of the outermost electron in potassium:

  • n = 4.
  • l  = 1.
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Explanation:

Refer to the electron configuration of a potassium atom. The outermost electron in a ground-state potassium atom is in the 4s orbital (fourth s orbital.)

The quantum number n (the principal quantum number) specifies the main energy shell of an electron. This electron is in the fourth main energy shell (as seen in the number four in the orbital.) Hence, n = 4 for this electron.

The quantum number l (the angular momentum quantum number) specifies the shape (s, p, d, etc.) of an electron. l = 1 for s\! orbitals (such as the one that contains this electron.

Quantum numbers n and l specify the shape of an orbital. On the other hand, the magnetic quantum number m_l specifies the orientation of these orbitals in space.

However, s orbitals are spherical. Regardless of the value of n, the only possible m_l value for electrons in s\! orbitals is m_l = 0.

The spin quantum number m_s distinguishes between the two electrons in an orbital. The two possible values of m_s \! are (+1/2) and (-1/2). Typically, the first electron in an orbital is assigned an upward (\uparrow) spin, which corresponds to m_s = (+1/2).

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