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Sloan [31]
2 years ago
13

How many grams of oxygen gas are required to produce 65.75 grams of steam?

Chemistry
1 answer:
Nana76 [90]2 years ago
3 0

Answer:

The mass of oxygen gas required to produce 65.75 grams of steam is approximately 162.2 grams

Explanation:

From the question, we have the following chemical reaction equation;

2C₃H₁₈(l) + 25O₂ (g) → 16CO₂(g) + 18H₂O (g)

The molar mass of oxygen, O₂ = 32 g/mol

The molar mass of steam, H₂O = 18.01528 g/mol

25 moles of oxygen are required to produce 18 moles of steam

Therefore, according to  Proust's law of definite proportions;

(32 × 25) g of oxygen are required to produce (18 × 18.01528) g of steam

65.75 g of steam will be produced by (32 × 25)/(18 × 18.01528) × 65.75 g ≈ 162.2 g of oxygen O₂.

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What volume of 24% trichloroacetic acid (tca) is needed to prepare eight 3 ounce bottles of 10% tca solution?
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Answer:

295.7 mL of 24% trichloroacetic acid (tca) is needed .

Explanation:

Let the volume of 24% trichloroacetic acid solution be x

Volume of required 10% trichloroacetic acid solution =8 bottles of 3 ounces

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Amount of trichloroacetic acid in 24% solution of x volume of solution will be equal to amount of trichloroacetic acid in 10% solution of volume 709.68 mL.

x\times \frac{24}{100}=709.68 mL\times \frac{10}{100}

x = 295.7 mL

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What volume of water is needed for 0.196 mol of CdCl2 to prepare a 3.91 M solution? L
Brilliant_brown [7]

0.050 litres of the water will be required to make a 3.91 M solution with 0.196 moles in it.

Explanation:

Data given:

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putting the values in the above formula and rearranging it for volume:

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Molarity is the number of moles present in a given volume of solution which is given in litres. It is the measurement of the concentration of particular solute in a solution.

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