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Pavel [41]
4 years ago
15

Calculate 8 ∙ 10-4 divided by 2 ∙ 102.

Physics
2 answers:
artcher [175]4 years ago
4 0
8 * 10 - 4 
= 80 - 4
= 76

2 * 102 = 204

76/204 = 19/51

Hope this helps!
KatRina [158]4 years ago
4 0

Explanation :

Here, 8\times 10^{-4} is numerator and 2\times 10^{2} is the denominator.

Two numbers are given i.e.

n_1=8\times 10^{-4}

n_2=2\times 10^{2}

We have to divide these two numbers.

\dfrac{n_1}{n_2}=\dfrac{8\times 10^{-4}}{2\times 10^{2}}

4\times 10^{-6}

Hence, this is the required solution.                  

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Lilly covered the same distance in less time, and both girls
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3 0
3 years ago
Suppose that a balloon is being filled with air at a rate of 10 cm3/s. (Assume that theballoon is a perfect sphere.) At what rat
Basile [38]

Answer:

Therefore the surface area of the balloon is increased at 4 cm³/s.

Explanation:

The balloon is being filled with air at a rate of 10 cm³/s

It means the volume of the balloon is increased at a rate 10 cm³/s.

i.e \frac{dv}{dt} =10 cm^3/s

Consider r be the radius of the balloon.

The volume of of a sphere is

v=\frac{4}{3} \pi r^3

Differentiate with respect to t

\frac{dv}{dt} =\frac{4}{3} \pi \times 3r^2\frac{dr}{dt}

\Rightarrow 10 =4\pi r^2\frac{dr}{dt}

\Rightarrow \frac{dr}{dt}=\frac{10}{4\pi r^2}

The surface of area of the balloon is(S) = 4\pi r^2

S=4\pi r^2

Differentiate with respect to t

\frac{dS}{dt} =4\pi\times2r\frac{dr}{dt}

\Rightarrow \frac{dS}{dt} =8\pi r\frac{dr}{dt}

Putting the value of \frac{dr}{dt}

\Rightarrow \frac{dS}{dt} =8\pi r\times\frac{10}{4\pi r^2}

\Rightarrow \frac{dS}{dt} =\frac{20}{ r}

Given that r = 5 cm

[\frac{dS}{dt}]_{r=5} =\frac{20}{ 5}  =4 cm³/s

Therefore the surface area of the balloon is increased at 4 cm³/s.

5 0
4 years ago
A small person was running way faster than a bigger person that weighed more collided in a football game. Who would be pushed ba
Semenov [28]

Answer:

smaller one

Explanation:

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5 0
3 years ago
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emmasim [6.3K]

Answer:

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