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3 years ago

A boat travel in a straight line at a velocity of 23 m/so and has a mass of 1000 know what is the boats momentum

1 answer:

7 0

So all you have to do is use this equation P=mv . the "m" as you guessed it represents mass in Kilograms, and the "v" represents velocity. The capital P is used to represent momentum, so all you have to do is plug in. P= 1000kg • 23 m/s which would give you 23,000 kg/m/s but since you're talking about a boat, you would have to convert the tons to kilograms (which I'm assuming that's what the unit is) in that case it would be approximately... 907,185 kg, but we aren't done yet. So that would leave you with 20,8652,55 kg/m/s. Theres a simple reason for converting to Kg, and that's because it's a rule in the math of calculating momentum. Good day, to you !

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4 years ago

#26 question

4vir4ik [10]

So, the time that taken for the astronaut to fall to the surface of the moon is <u>2.5 s.</u>

<h3>Introduction</h3>

Hi ! In this question, I will help you. In this question, you will learn about the fall time of the free fall motion. Free fall is a downward vertical motion without being preceded by an initial velocity. When moving in free fall, the time required can be calculated by the following equation:

$\sf{h = \frac{1}{2} \cdot g \cdot t^2}$

$\sf{\frac{2 \cdot h}{g} = t^2}$

$\boxed{\sf{\bold{t = \sqrt{\frac{2 \cdot h}{g}}}}}$

With the following condition :

t = interval of the time (s)
h = height or any other displacement at vertical line (m)
g = acceleration of the gravity (m/s²)

<h3>Problem Solving</h3>

We know that :

h = height = 5.00 m
g = acceleration of the gravity = 1.6 m/s²

What was asked :

t = interval of the time = ... s

Step by step :

$\sf{t = \sqrt{\frac{2 \cdot h}{g}}}$

$\sf{t = \sqrt{\frac{2 \cdot 5}{1.6}}}$

$\sf{t = \sqrt{6.25}}$

$\boxed{\sf{t = 2.5 \: s}}$

<h3>Conclusion</h3>

So, the time that taken for the astronaut to fall to the surface of the moon is 2.5 s.

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