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Vedmedyk [2.9K]
2 years ago
8

Suppose a star has the same apparent brightness as Alpha Centauri A ( 2.7×10−8watt/m2 ) but is located at a distance of 300 ligh

t-years. What is its luminosity?
Physics
1 answer:
iragen [17]2 years ago
6 0

For  a star that has the same apparent brightness as Alpha Centauri A ( 2.7×10−8watt/m2 is mathematically given as

L=2.7*10^30w

<h3> What is its luminosity?</h3>

Generally, the equation for the luminosity  is mathematically given as

L=4*\pi^2*b

Therefore

L=4*\pi^2*b

L=4* \pi *(2.83*10^{18})*2.7*10^{-8}

L=2.7*10^30

In conclusion, the luminosity

L=2.7*10^30w

Read more about Light

brainly.com/question/25770676

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The drawing shows a bicycle wheel resting against a small step whose height is h = 0.110 m. The weight and radius of the wheel a
Pavel [41]

Answer:

F=27.39N

Explanation:

Take sum of torques at the point the step touches the wheel, that eliminates two torques

ΣT=T_{N}+T_{f}+T_{W}

Since we are looking for when the wheel just starts to rise up N-> 0 so no torque due to normal force

T_{N}=0

The perpendicular lever arm for the F force is R-h

T_{f}=F*(r-h)

And the T of gravity according to the image

T_{W}=W*(\sqrt{r^2-(r-h)^2}

ΣT=0

T_{N}+T_{f}+T_{W}=0

F*(r-h)+W*(\sqrt{r^2-(r-h)^2}=0

F=\frac{W*(\sqrt{r^2-(r-h)^2}}{r-h}

F=\frac{24.9 N*(\sqrt{0.336^2-(0.336-0.110)^2}}{(0.336-0.11)}

F=27.39N

4 0
3 years ago
What is a scientific model?Question 2 options:A group of objects that interact with each other.A complex system made of many sma
HACTEHA [7]

Answer:

A scientific model is a way of representing a system to better understand it's behavior

Explanation:

5 0
3 years ago
Have you heard of any particle, which moves faster than light? Explore the recent researches and find about it.
Lisa [10]

Answer:

There is nothing faster then light

Explanation:

4 0
3 years ago
On a touchdown attempt, 95.00 kg running back runs toward the end zone at 3.750 m/s. A 113.0 kg line-backer moving at 5.380 m/s
dsp73

Answer:

(a) 1.21 m/s

(b) 2303.33 J, 152.27 J

Explanation:

m1 = 95 kg, u1 = - 3.750 m/s, m2 = 113 kg, u2 = 5.38 m/s

(a) Let their velocity after striking is v.

By use of conservation of momentum

Momentum before collision = momentum after collision

m1 x u1 + m2 x u2 = (m1 + m2) x v

- 95 x 3.75 + 113 x 5.38 = (95 + 113) x v

v = ( - 356.25 + 607.94) / 208 = 1.21 m /s

(b) Kinetic energy before collision = 1/2 m1 x u1^2 + 1/2 m2 x u2^2

                                               = 0.5 ( 95 x 3.750 x 3.750 + 113 x 5.38 x 5.38)

                                               = 0.5 (1335.94 + 3270.7) = 2303.33 J

Kinetic energy after collision = 1/2 (m1 + m2) v^2                

                                                = 0.5 (95 + 113) x 1.21 x 1.21 = 152.27 J

4 0
3 years ago
An iron ball is dropped at a height of 10 m from the surface of the moon.
galben [10]

Answer:

3.51s

Explanation:

There are many students who can not get answers step by step and on time

So there are a wats up group where you can get help step by step and well explained by the trusted experts.

3 0
3 years ago
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