For a star that has the same apparent brightness as Alpha Centauri A ( 2.7×10−8watt/m2 is mathematically given as
L=2.7*10^30w
Generally, the equation for the luminosity is mathematically given as
L=4*\pi^2*b
Therefore
L=4* \pi *(2.83*10^{18})*2.7*10^{-8}
L=2.7*10^30
In conclusion, the luminosity
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Answer:
Explanation:
We are given that
Diameter=d=
Thickness=
Radius=
Using
Dielectric constant=8
Resistance =
Internal specific resistance=r=100 ohm cm=
Using 1 m=100 cm
Internal resistance per unit length=
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Answer:it’s c SrBr2