Answer:
Search engines use many different "clues" about the quality of a website's content to determine how a page should be ranked in search results.
Explanation:
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Answer:
The area of solar panel needed in Buffalo is 22.83 m²
The area of solar panel needed in Phoenix is 31 m²
Explanation:
<u>FOR BUFFALO</u>:
First we, calculate the the annual power requirement by dividing the energy by the time of 1 year.
Therefore,
Power Requirement = P = 6000 KWhr/(1 yr)(365 days/yr)(24 hr/day)
P = 684.93 W
Now, to calculate the area we use the formula:
Area = A = P/(Annual Insolation)(Conversion Factor)
A = 684.93 W/(200 W/m²)(0.15)
<u>A = 22.83 m²</u>
<u>FOR PHOENIX</u>:
First we, calculate the the annual power requirement by dividing the energy by the time of 1 year.
Therefore,
Power Requirement = P = 11000 KWhr/(1 yr)(365 days/yr)(24 hr/day)
P = 1255.7 W
Now, to calculate the area we use the formula:
Area = A = P/(Annual Insolation)(Conversion Factor)
A = 1255.7 W/(270 W/m²)(0.15)
<u>A = 31 m²</u>
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Answer:
Thermal efficiency of cycle = 0.314
Quality of exhaust steam = 0.959
Explanation:
Answer:
The question is incomplete, the complete question is:
Which of the following is not a reason to give yourself extra "cushion" when driving?
A. Poor visibility B. Poor road conditions C. Inclement weather D. None of these.
The correct answer is D. None of these.
Explanation:
All the options are not reasons to give yourself an extra cushion when driving, rather they are reasons that are not favorable to driving at all.
A cushion is a certain amount of distance you are supposed to keep between you and the car in front of you to allow easy maneuvering in any condition.
A typical cushion is 3 seconds between you and the car in front of you, in less than perfect conditions like bad weather or poor road conditions an additional second must be added to it.
Answer:
The speed is the same at 1.5 m/s while
The work done by the force F is 0.4335 J
Explanation:
Here we have angular acceleration α = v²/r
Force = ma = 2.8 × 1.5²/r₁
and ω₁ = v₁/r₁ = ω₂ = v₁/r₂
The distance moved by the force = 600 - 300 = 300 mm = 0.3 m
If the velocity is constant
The speed is 1.5 m/s while the work done is
2.8 × 1.5²1/(effective radius) ×0.3
r₁ = effective radius
2.8*9.81 = 2.8 × 1.5²/r₁
r₁ = 0.229
The work done by the force = 2.8 × 1.5²*1/r₁ *0.3 = 0.4335 J