Answer:
- import java.util.Scanner;
- import java.util.Random;
- public class Main {
-
- public static void main(String[] args) {
-
- Scanner input = new Scanner(System.in);
- Random rand = new Random();
-
- System.out.print("Enter number of questions you wish to practice: ");
- int n = input.nextInt();
-
- int i = 1;
- while(i <= n){
- int num1 = 1 + rand.nextInt(10);
- int num2 = 1 + rand.nextInt(10);
- int answer = num1 * num2;
- System.out.print("Question " + i + ": " + num1 + " x " + num2 + " = ");
- int response = input.nextInt();
-
- if(response == answer){
- System.out.println("Correct answer!");
- }
- else{
- System.out.println("Wrong answer. It should be " + answer);
- }
- i++;
- }
- }
- }
Explanation:
Firstly, we import Scanner and Random classes (Line 1-2) as we need to get user input for number of questions and generate random number in each question.
Next, create a Scanner and Random object (Line 7-8). Prompt user to input number of question and get the input using the Scanner object (Line 10-11).
Next create a while loop and set the condition to loop for n number of times (based on number of questions) (Line 14). In the loop, use Random object nextInt method to generate two integers between 1 -10 (Line 15-16). Prompt user to input an answer using the Scanner object (Line 18-19). If the response is matched with answer print a correct message (Line 21-22) other wise inform user they write a wrong answer and show the correct answer (Line 24-25).
Answer:
after 8 stepshddnffuddbnggkbdbkloyr
Answer:
<em>Option D </em>
<em>Electric meter is used to </em><em>measure</em><em> the amount of electric current</em>
Answer:
81.76 N/mm² ( MPa), 1.71233
Explanation:
Modulus of elasticity = stress / strain
stress = modulus of elastic × strain
strain = ΔL / L = 250.28 mm - 250 mm / 250 mm = 0.00112
Modulus of elasticity E = 73 GPa = 73 × 10³ MPa where 1 MPa = 1 N/mm²
E = 73 × 10³N/mm²
stress = 73 × 10³N/mm²× 0.00112 = 81.76 N/mm² ( MPa)
b) Factor of safety = maximum allowable stress / induced stress = 140 MPa / 81.76 MPa = 1.71233
Biometric sensors are used to collect measurable biological characteristics from a human being, which can then be used in conjunction with biometric recognition algorithms to perform automated person identification.
