Nodal analysis is based on Kirchhoff's first (Current) law (KCL)
The value of the voltage V₂ is -6 V
The reason the above value is correct is as follows:
From the given parameters of the circuit are;
= 8 V, R₁ = 100 Ω, R₂ = 200Ω, R₃ = 300Ω, R₄ = 600
Ω, = 10 mA
The circuit simplified the as follows;
<em>R₁</em> and <em>R₂ </em>which are in <em>series </em>are combined to give;
= R₁ + R₂
Therefore;
= 100 Ω + 200 Ω = 300 Ω
R₃ and R₄ are combined, given that they are parallel circuits to give;

Therefore;

The simplified circuit is as shown in the attached diagram
By <em>Kirchhoff's current law</em>, KCL, at node b, we have;
I₁ + I₂ + I₃ = 0
Where;
,
, and I₃ =
= 10 mA
Plugging in the known values gives;
= V₂

2 × (
) + 3 ×
= 600 × 10×10⁻³
5·
- 16 = -6
= (-6 + 16)/5 = 10/5 = 2
Therefore,
= 10 V
V₂ =
∴ V₂ = 2 V - 8 V = -6 V
V₂ = -6 V
The value of the voltage V₂ = -6 V
Learn more about nodal analysis here:
brainly.com/question/16699518