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grandymaker [24]
3 years ago
12

The lewis electron-dot structure of n2 has ________ nonbonding electrons pairs, ________ bonding electron pairs, and a bond orde

r of ________.
Chemistry
1 answer:
Novosadov [1.4K]3 years ago
6 0
The answer to this question would be: 2; 3; 3

In nitrogen gas structure, there are 5 total electron pairs which were made by 2.5 electron pairs(5 electrons) for every nitrogen atom. In the middle, you will found 3 pair making bond order 3. In each nitrogen, there will be 1 nonbonding electron making it a total 2 unbonding electron pairs.
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Classify each of the following as a strong acid or a weak acid and indicate how each should be written in aqueous solution. Clas
JulijaS [17]

Answer:

HCN, weak acid

H⁺, Br⁻, strong acid

Explanation:

Hydrocyanic acid is a weak acid, according to the following equation.

HCN(aq) ⇄ H⁺(aq) + CN⁻(aq)

Thus, it should be written in the undissociated form (HCN).

Hydrobromic acid is a strong acid, according to the following equation.

HBr(aq) ⇒ H⁺(aq) + Br⁻(aq)

Thus, it should be written in the ionic form (H⁺, Br⁻).

7 0
2 years ago
Jill graphs the speed of a model train that is travelling at a speed of 15 kilometers per hour. Which graph shows the speed of t
Tasya [4]

Answer:c

Explanation:

8 0
3 years ago
Equal molar quantities of Ca2 and EDTA (H4Y) are added to make a 0.010 M solution of CaY2- at pH 10. The formation constant for
abruzzese [7]

Answer:

the concentration of free Ca2⁺ in this solution is 7.559 × 10⁻⁷

Explanation:

Given the data in the question;

Ca^{2+ + y^{4- ⇄  CaY^{2-

Formation constant Kf

Kf = CaY^{2- / ( [Ca^{2+][y^{4-] ) = 5.0 × 10¹⁰

Now,

[y^{4-] = \alpha _4CH_4Y; ∝₄ = 0.35

so the equilibrium is;

Ca^{2+ + H_4Y ⇄  CaY^{2- + 4H⁺

Given that; CH_4Y = Ca^{2+     { 1 mol Ca^{2+  reacts with 1 mol H_4Y  }

so at equilibrium, CH_4Y = Ca^{2+ = x

∴

Ca^{2+ + y^{4- ⇄  CaY^{2-

x        + x         0.010-x

since Kf is high, them x will be small so, 0.010-x is approximately 0.010

so;

Kf = CaY^{2- / ( [Ca^{2+][y^{4-] ) =  CaY^{2- / ( [Ca^{2+][\alpha _4CH_4Y] )  = 5.0 × 10¹⁰

⇒ CaY^{2- / ( [Ca^{2+][\alpha _4CH_4Y] )  = 5.0 × 10¹⁰

⇒ 0.010 / ( [x][ 0.35 × x] )  = 5.0 × 10¹⁰

⇒ 0.010 / 0.35x²  = 5.0 × 10¹⁰

⇒ x² = 0.010 / ( 0.35 × 5.0 × 10¹⁰ )

⇒ x² = 0.010 / 1.75 × 10¹⁰

⇒ x² = 0.010 / 1.75 × 10¹⁰

⇒ x² = 5.7142857 × 10⁻¹³

⇒ x = √(5.7142857 × 10⁻¹³)

⇒ x = 7.559 × 10⁻⁷

Therefore, the concentration of free Ca2⁺ in this solution is 7.559 × 10⁻⁷

8 0
2 years ago
What is the name of the compound with the formula B2C14?​
agasfer [191]

Answer:

Diboron tetrachloride --->  B2Cl4

6 0
3 years ago
4. Describe the movement of the water molecules at cold temperatures.
kenny6666 [7]

Answer:

Point out to students that molecules of hot water are moving faster and are slightly further apart. The molecules of cold water are moving slower and are a little closer together. If students do not notice a difference, move the slider all the way to the left again and then quickly to the right.

2. How do molecules move in cold water?

Compare the speed of molecules in hot water compared to molecules in cold water? Water molecules move faster in hot water and slower in cold water. water molecules in cold, room temperature, and hot water. most of the liquid.

3 0
2 years ago
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