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Contact [7]
2 years ago
14

A mixture of c2h2 and ch4 has a total mass of 230.9 g. when this mixture reacts completely with excess oxygen, the co2 and h2o p

roducts have a combined mass of 972.7 g. what mass of ch4 was present in the initial mixture?
Chemistry
1 answer:
Salsk061 [2.6K]2 years ago
6 0
Interesting problem. Thanks for posting.

C2H2 + (3/2)02 ====>  H2O + 2CO2
CH4 +  2O2 =====> 2H2O + CO2

The molar mass of C2H2 = 2*12 + 2*1 = 26
The molar mass of CH4 = 1*12 + 4*1 = 16

The number of moles of C2H2 = x
The number of moles of  CH4 = y
26x + 16y = 230.9 grams

For water we get (from the C2H2). Water has a molar mass of 2*1 + 16 = 18

x*18 See the balanced equation to see what it is the same number of moles as C2H2
From the methane we get
y*18
2*y* 18. Again see the balanced equation to see where that 2 came from.
18x + 36y is the total amount of water. 

Now for the CO2. CO2 has a molar mass of 12 + 2*16 = 44
From C2H2  we get 2*44*x = 88x grams of CO2
From CH4 we get 1*y*44 grams of CO2
88x + 44y for CO2

Now we total to get the grand total of water and CO2
18x + 44y + 88x + 44y = 972.7 grams total.
106x + 88y =  972.7

Two equations, two unknowns, we should be able to solve this problem
26x + 16y = 230.9
106x + 88y = 972.7

I'm not going to go through the math unless you request me to do so. 
x = 8.03 moles
y = 1.38 moles 

The initial amount of C2H2 was 8.03 * 26 = 208.78
The initial amount of CH4 was 16*1.38 = 22.08
The total (as a check is 230.86 which is pretty close to the given amount.
So Methane's mass in the initial givens was 22.08 grams.
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5 0
2 years ago
Use the value of the Avogadro constant (6.02 × 1023 mol–1) to calculate the total number of atoms in 7.10 g of chlorine atoms. (
kolbaska11 [484]

The total number of atoms in 7.10g of chlorine is 1.204 × 10²³atoms.

HOW TO CALCULATE NUMBER OF ATOMS:

  • The number of atoms in a substance can be calculated by multiplying the number of moles in that substance by Avogadro's number as follows:

  • no. of atoms = no. of moles × 6.02 × 10²³ mol-¹

  • The number of moles in 7.10g of Cl is calculated as follows:

no. of moles = mass ÷ molar mass

no. of moles = 7.10g ÷ 35.5g/mol

no. of moles = 0.2mol

no of atoms = 0.2mol × 6.02 × 10²³

no. of atoms = 1.204 × 10²³atoms.

  • Therefore, the total number of atoms in 7.10g of chlorine is 1.204 × 10²³atoms.

Learn more: brainly.com/question/15488332?referrer=searchResults

6 0
2 years ago
Convert 13.4 degrees celcius into kelvin​
Alenkasestr [34]

Answer:

286.55K

Explanation:

To convert to kelvin , add 237 .15

13.4\°C + 273.15 = 286.55K

5 0
2 years ago
Read 2 more answers
3. How many molecules are in 2.10 moles of H2O?
AnnZ [28]

Answer:

<h2>1.264 × 10²⁴ molecules</h2>

Explanation:

The number of molecules can be found by using the formula

N = n × L

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 2.10 × 6.02 × 10²³

We have the final answer as

<h3>1.264 × 10²⁴ molecules</h3>

Hope this helps you

5 0
3 years ago
How many grams of lithium are in 6.02*10^21 atoms
valentinak56 [21]

the answer is 0.0693769. 6.02x10^21 x6.94/ 6.022x10^23 is the formua you would use.

7 0
3 years ago
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