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PolarNik [594]
2 years ago
9

Hot air is more / less dense than cooler air. Choose the correct one.

Chemistry
1 answer:
Paha777 [63]2 years ago
4 0

it is less dense then cold

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Calculate the molarity of a solution made by dissolving 4.0 g of calcium bromide, CaBr2, in enough water to give 200 mL of solut
Troyanec [42]

Answer:

0.1 M

Explanation:

Molarity = number of moles / litres of solution.

4 g of calcium bromide = 0.02 mol

(found by dividing 4 g by the atomic mass of CaBr2, which is 199.886)

200 mL of solution = 0.2 litres

Molarity = 0.02 mol / 0.2 L = 0.1 M

8 0
3 years ago
Accuracy vs. Precision
Oksi-84 [34.3K]

Answer:

Accuracy is the closeness to the specific target and precision is the closeness of the measurements to each other.

3 0
3 years ago
Read 2 more answers
How many moles are there in 24.00 g of NaCl
Elis [28]

Answer:

The answer to your question is 0.41 moles

Explanation:

Data

moles of NaCl = ?

mass of NaCl = 24 g

Process

To solve this problem just calculate the molar mass of NaCl, and remember that the molar mass of any substance equals to 1 mol.

1.- Calculate the molar mass

NaCl = 23 + 35.5 = 58.5 g

2.- Use proportions and cross multiplication

               58.5 g of NaCl ------------------- 1 mol

               24.0 g               ------------------- x

                     x = (24 x 1) / 58.5

                     x = 0.41 moles

6 0
3 years ago
Nombra cada uno de los siguientes hidrocarburos de acuerdo a las reglas de la IUPAC
myrzilka [38]

Answer:

i) ciclobutano

ii) 3-etil-4-metil ciclopenteno

Explanation:

Toda la idea de la nomenclatura IUPAC es permitir que la estructura de la sustancia se derive de su nombre y viceversa.

La nomenclatura IUPAC es un sistema universalmente aceptado para nombrar compuestos químicos.

los nombres de los compuestos enumerados son;

i) ciclobutano

ii) 3-etil-4-metil ciclopenteno

3 0
3 years ago
...............………...mkmlkml;m
bagirrra123 [75]

Answer:

390

Explanation:

Specific heat capacity= heat/mass × temperature

x = 2925 \div 0.5 \times 15 = 390

Remember you convert gram into kilogram and 1 gram =0.001 kilogram

5 0
3 years ago
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