Answer:
In x: 4-1=3
In y: -2
Cartesian coordinates: (3,-2)
Step-by-step explanation:
If we move horizontally we must consider only the x axis, if we move to east it is positive, and if we move to west it is negative.
f we move vertically we must consider only the y axis, if we move to north it is positive, and if we move to south it is negative.
Given a N quantity of numbers, the Geometric Mean is equal to the N-th root of product of the N numbers
In this case, we have two numbers, then we need to multiply them and take square root:
![\sqrt{40\cdot15}=\sqrt[]{600}=\sqrt[]{100\cdot6}=\sqrt[]{100}\cdot\sqrt[]{6}=10\sqrt[]{6}](https://tex.z-dn.net/?f=%5Csqrt%7B40%5Ccdot15%7D%3D%5Csqrt%5B%5D%7B600%7D%3D%5Csqrt%5B%5D%7B100%5Ccdot6%7D%3D%5Csqrt%5B%5D%7B100%7D%5Ccdot%5Csqrt%5B%5D%7B6%7D%3D10%5Csqrt%5B%5D%7B6%7D)
The answer is:
10√6
Rounded is Approximately 24.5
Do you mean
![3 \sqrt[3]{125}](https://tex.z-dn.net/?f=3%20%5Csqrt%5B3%5D%7B125%7D%20)
or
![\sqrt[3]{125}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%7D%20)
remember that
![\sqrt[n]{x^m}=x^\frac{m}{n}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%5Em%7D%3Dx%5E%5Cfrac%7Bm%7D%7Bn%7D)
resolve the
![\sqrt[3]{125}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%7D)
part first
![\sqrt[3]{125}=](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%7D%3D)
![\sqrt[3]{5^3}=](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B5%5E3%7D%3D)



so
![3 \sqrt[3]{125}=3*5=15](https://tex.z-dn.net/?f=3%20%5Csqrt%5B3%5D%7B125%7D%3D3%2A5%3D15%20)
or
![\sqrt[3]{125} =5](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%7D%20%3D5)
not sure which one you mean
You have to be a bit more specific than that