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Helga [31]
3 years ago
10

I WILL MARK AS BRANLIEST!

Mathematics
1 answer:
PolarNik [594]3 years ago
8 0

Answer:

0.5 pounds is one game

2 pounds is one textbook

Step-by-step explanation:

g = games

t = textbooks

Let's start with how much a game weighs. We know that when Chad added two more games the weight of the box increased by one pound (it was previously 21 pounds and then went to 22 when the two games were added). This means one game equals half of a pound (or 0.5 lbs.)...

2g = 1

\frac{2g}{2} = \frac{1}{2}  -> if you divide one side by two, you must do the same to the other.

g = \frac{1}{2} = 0.5

Now that we know the weight of the games, we can figure out the weight of the textbooks.

6g + 9t = 21 -> 6 games and 9 textbooks weigh 21 pounds.

Plugging in that each game is 0.5 pounds...

6(0.5) + 9t = 21

3 + 9t = 21

3 - 3 + 9t = 21 - 3

9t = 18

\frac{9t}{9} = \frac{18}{9}

t = 2

That means that each textbook equals 2 pounds.

I hope this helps!

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\huge \boxed{\mathbb{QUESTION} \downarrow}

  • How do you simplify this?
  • x²y+xy² / y²+2/5 × xy

\large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}

\sf\frac{  { x  }^{ 2  }  y+x { y  }^{ 2  }    }{  { y  }^{ 2  }  + \frac{ 2  }{ 5  }   \times  xy  } \\

Factor the expressions that are not already factored.

_____

<u>How </u><u>to</u><u> factorise</u><u> </u><u>:</u><u>-</u>

<u>NUMERATOR</u> \downarrow

\sf \: x ^ { 2 } y + x y ^ { 2 }

Factor out xy.

\sf \: xy\left(x+y\right)

<u>DENOMINATOR</u> \downarrow

\sf{ y  }^{ 2  }  + \frac{ 2  }{ 5  }   \times  xy \\

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\sf \: {\frac{1}{5}y\left(2x+5y\right)}  \\

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\sf\frac{xy\left(x+y\right)}{\frac{1}{5}y\left(2x+5y\right)}  \\

Cancel out y in both the numerator and denominator.

\sf\frac{x\left(x+y\right)}{\frac{1}{5}\left(2x+5y\right)}  \\

Expand the expression.

\sf\frac{x^{2}+xy}{\frac{2}{5}x+y}  \\

This can further simplified to as \downarrow

=    \boxed{\boxed{\bf\frac{5x\left(x  +y\right)}{2x+5y}}}

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