Answer:
Each student ticket costs $8.33
Each adult ticket costs $15.34
Step-by-step explanation:
At Niagra High, Mr. Borton bought 4 student tickets and 2 adult tickets for the high school musical which cost $64. then Mrs. Gelvoria bought 3 student tickets and 3 adult tickets for the show and it cost her $72. How much are each type of tickets?
s = cost of each student ticket
a = cost of adult ticket
Our system of equations:
4s + 2a = 64
3s + 3a = 71
-3(4s + 2a = 64) ==> -12s - 6a = -192
2(3s + 3a = 71) ==> 6s + 6a = 142
-12s - 6a = -192
6s + 6a = 142
-6s = -50
/-6 /-6
s = $8.33 (the cost of each student ticket)
Now, let's find the cost of each adult ticket:
4s + 2a = 64
4(8.33) + 2a = 64
33.32 + 2a = 64
-33.32 -33.32
2a = 30.68
/2 /2
a = 15.34 (the cost of each adult ticket)
(x, y) ==> (8.33, 15.34)
Check your answer:
4s + 2a = 64
4(8.33) + 2(15.34) = 64
33.32 + 30.68 = 64
64 = 64
This statement is true
Hope this helps!
Answer:
x=1.5
Step-by-step explanation:
So far, you've only defined f(x). You haven't asked a question.
Answer:
( 1, -4)
Step-by-step explanation:
To find this answer you go over 2 to the right on the x-axis, then go down 6 on the y-axis. This gives ( 1, -4).
P=2w+(2w-3)
60=4w-3
63=4w
15.75=w
l=2w-3
l=(2×15.75)-3
l=31.5-3
l=28.5
This answer doesn't add up so if you meant the COMBINED width then:
P=w+(2w-3)
60=3w-3
63=3w
21=w
l=2(21)-3
l=42-3
l=39
(This answer checks out so this is probably what you meant hope I helped)