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2 years ago

Help me there’s a time limit on this

Mathematics

2 answers:

NikAS [45]2 years ago

7 0

11 hours bc 5 times 11 equals 55

xxMikexx [17]2 years ago

4 0

Answer:

is ll hrs is the answer hurry

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what is 900+100 I'm stuck 100 points for the people who can answer i know its 1000 still 100 points go listen to (joey trap) bar

charle [14.2K]

Answer:

1000

Step-by-step explanation:

x = 1, y = -1, and z = 2

5 0

2 years ago

Read 2 more answers

The angle of elevation from me to the top of a hill is 51 degrees. The angle of elevation from me to the top of a tree is 57 deg

julia-pushkina [17]

Answer:

Approximately $101\; \rm ft$ (assuming that the height of the base of the hill is the same as that of the observer.)

Step-by-step explanation:

Refer to the diagram attached.

Let $\rm O$ denote the observer.
Let $\rm A$ denote the top of the tree.
Let $\rm R$ denote the base of the tree.
Let $\rm B$ denote the point where line $\rm AR$ (a vertical line) and the horizontal line going through $\rm O$ meets. $\angle \rm B\hat{A}R = 90^\circ$ .

Angles:

Angle of elevation of the base of the tree as it appears to the observer: $\angle \rm B\hat{O}R = 51^\circ$ .
Angle of elevation of the top of the tree as it appears to the observer: $\angle \rm B\hat{O}A = 57^\circ$ .

Let the length of segment $\rm BR$ (vertical distance between the base of the tree and the base of the hill) be $x\; \rm ft$ .

The question is asking for the length of segment $\rm AB$ . Notice that the length of this segment is $\mathrm{AB} = (x + 20)\; \rm ft$ .

The length of segment $\rm OB$ could be represented in two ways:

In right triangle $\rm \triangle OBR$ as the side adjacent to $\angle \rm B\hat{O}R = 51^\circ$ .
In right triangle $\rm \triangle OBA$ as the side adjacent to $\angle \rm B\hat{O}A = 57^\circ$ .

For example, in right triangle $\rm \triangle OBR$ , the length of the side opposite to $\angle \rm B\hat{O}R = 51^\circ$ is segment $\rm BR$ . The length of that segment is $x\; \rm ft$ .

$\begin{aligned}\tan{\left(\angle\mathrm{B\hat{O}R}\right)} = \frac{\,\rm {BR}\,}{\,\rm {OB}\,} \; \genfrac{}{}{0em}{}{\leftarrow \text{opposite}}{\leftarrow \text{adjacent}}\end{aligned}$ .

Rearrange to find an expression for the length of $\rm OB$ (in $\rm ft$ ) in terms of $x$ :

$\begin{aligned}\mathrm{OB} &= \frac{\mathrm{BR}}{\tan{\left(\angle\mathrm{B\hat{O}R}\right)}} \\ &= \frac{x}{\tan\left(51^\circ\right)}\approx 0.810\, x\end{aligned}$ .

Similarly, in right triangle $\rm \triangle OBA$ :

$\begin{aligned}\mathrm{OB} &= \frac{\mathrm{AB}}{\tan{\left(\angle\mathrm{B\hat{O}A}\right)}} \\ &= \frac{x + 20}{\tan\left(57^\circ\right)}\approx 0.649\, (x + 20)\end{aligned}$ .

Equate the right-hand side of these two equations:

$0.810\, x \approx 0.649\, (x + 20)$ .

Solve for $x$ :

$x \approx 81\; \rm ft$ .

Hence, the height of the top of this tree relative to the base of the hill would be $(x + 20)\; {\rm ft}\approx 101\; \rm ft$ .

6 0

3 years ago

Twice the difference of a number and 5 is 2.<br> Use the variable W for the unknown number

Kitty [74]

Hey there!

The difference of a number, w, and 5 will be represented by (w – 5). Twice this would simply multiply this expression by 2, making it 2(w – 5). Finally, just set this expression equal to 2. Your equation is 2(w – 5) = 2.

To solve this, expand the two to the terms in parentheses. Then, solve the rest of the way as you would normally, using addition, subtraction, multiplication, or division to cancel out and move around terms. Remember, what you do on one side must be done to the other!

2(w – 5) = 2
(2*w – 2*5) = 2
(2w – 10) + 10 = (2) + 10
(2w) ÷ 2 = (12) ÷ 2
w = 6

Hope this helped you out! :-)

8 0

2 years ago

Nicole runs 6 miles in 44 minutes. At the same rate, how many minutes would she take to run 9 miles?

HACTEHA [7]

66 minutes is the correct answer

6 0

2 years ago

Someonepleasehelp me asap <br>evaluate (8)-2(15-8)

AnnZ [28]

Answer:

-6

Step-by-step explanation:

You have to multiple -2 by 15 and -8 separately

8 - 2(15-8)

8 -30 + 16

24-30 = -6

4 0

2 years ago