А<br> is a push or pull.

3. At an early age, what happened to Cesar’s home?

Doss [256]

Answer: He died later in 78 BC and was accorded a state funeral. Hearing of Sulla's death, Caesar felt safe enough to return to Rome. Lacking means since his inheritance was confiscated, he acquired a modest house in the Subura, a lower-class neighbourhood of Rome. hope this helps. Can u give me brainliest

Explanation:

3 0

3 years ago

The frequency of the musical note F#3 is 1.85x102 hertz. What is its period?

g100num [7]

The period of the musical note is $\text { 5. } 4 \times 10^{-3}$ seconds.

Answer: Option A

<u>Explanation:</u>

The frequency is defined as the number of oscillations or a complete cycle of wave occurred in a given time interval. So the frequency is inversely proportional to the time period. Thus the mathematical representation of frequency with time period is

$\text {Frequency}=\frac{1}{\text {Time period }}$

As the frequency is given as $1.85 \times 10^{2} \mathrm{Hz}$ , the time period can be found as

$\text { Time period }=\frac{1}{\text { Frequency }}$

Thus,

$\text { Time period }=\frac{1}{1.85 \times 10^{2}}=5.4 \times 10^{-3} \mathrm{s}$

Thus the time period for the frequency of the musical note is $\text { 5. } 4 \times 10^{-3}$ seconds.

5 0

3 years ago

Until he was in his seventies, Henri LaMothe excited audiences by belly-flopping from a height of 9 m into 32 cm. of water. Assu

baherus [9]

Answer:

823.46 kgm/s

Explanation:

At 9 m above the water before he jumps, Henri LaMothe has a potential energy change, mgh which equals his kinetic energy 1/2mv² just as he reaches the surface of the water.

So, mgh = 1/2mv²

From here, his velocity just as he reaches the surface of the water is

v = √2gh

h = 9 m and g = 9.8 m/s²

v = √(2 × 9 × 9.8) m/s

v = √176.4 m/s

v₁ = 13.28 m/s

So his velocity just as he reaches the surface of the water is 13.28 m/s.

Now he dives into 32 cm = 0.32 m of water and stops so his final velocity v₂ = 0.

So, if we take the upward direction as positive, his initial momentum at the surface of the water is p₁ = -mv₁. His final momentum is p₂ = mv₂.

His momentum change or impulse, J = p₂ - p₁ = mv₂ - (-mv₁) = mv₂ + mv₁. Since m = Henri LaMothe's mass = 62 kg,

J = (62 × 0 + 62 × 13.28) kgm/s = 0 + 823.46 kgm/s = 823.46 kgm/s