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faltersainse [42]
3 years ago
8

The force, F, of the wind blowing against a building is given by where V is the wind speed, rho the density of the air, A the cr

oss-sectional area of the building, and CD is a constant termed the drag coefficient. Determine the dimensions of the drag coefficient.
Physics
1 answer:
Sveta_85 [38]3 years ago
7 0

Answer:

dimensions of the drag coefficient is [M^0 L^0 T^0]

Drag coefficient is a dimensionless quantity

Explanation:

force is given byF=\frac{C_{D}  \rho V^2 A}{2}

we get expression for drag coefficient C_{D} =\frac{2F}{\rho V^2 A}

By substituting the dimensions  of the F,V,A and density , we get

C_{D} =\frac{[F]}{[\rho ][V]^2[A]} \\C_{D} =\frac{[MLT^{-2}]}{[ML^{-3} ][L T^{-1}]^2[L^2]} \\C_{D} =\frac{[MLT^{-2}]}{[ML^{-3} ][L^2 T^{-2}][L^2]} \\C_{D} =\frac{[MLT^{-2}]}{[MLT^{-2}]}\\C_{D}=[M^0 L^0 T^0]

Drag coefficient is a dimensionless

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8 0
3 years ago
A batter hits a 0.140-kg baseball that was approaching him at 19.5 m/s and, as a result, the ball leaves the bat at 44.8 m/s in
Arada [10]

Answer:

5295.3 N

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Hence the force exerted to generate such momentum within 1.7ms (0.0017s) is

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4 0
3 years ago
If I punch a wall, what is the Newton's 3rd Law Pair force?
UkoKoshka [18]
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3 years ago
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vovikov84 [41]

Answer:

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m = 76 kg, R = 840 N

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By use of Newton's second law

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840 = 76 ( 9.8 + a)

a = 1.25 m/s^2

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7 0
3 years ago
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