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Maslowich
3 years ago
14

When the distance between a point source of light and a light meter is reduced from 6.0m to 2.0 m, the intensity of illumination

at the meter will be the original value multiplied by _____.
Physics
1 answer:
Sergeeva-Olga [200]3 years ago
7 0

Answer:

Explanation:

Let the point source have power P .

At distance r , the intensity I

I = P / 4πr² . If intensity at 6 m and 2 m be I₁ and I₂

I₁ = P / 4π x 6²

I₂ =  P / 4π x 2²

I₁ / I₂ = 2² / 6²

= 1 / 9

I₂ = 9 I₁

Intensity will be 9 times that at 6 m .

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