When the distance between a point source of light and a light meter is reduced from 6.0m to 2.0 m, the intensity of illumination
at the meter will be the original value multiplied by _____.
1 answer:
Answer:
Explanation:
Let the point source have power P .
At distance r , the intensity I
I = P / 4πr² . If intensity at 6 m and 2 m be I₁ and I₂
I₁ = P / 4π x 6²
I₂ = P / 4π x 2²
I₁ / I₂ = 2² / 6²
= 1 / 9
I₂ = 9 I₁
Intensity will be 9 times that at 6 m .
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Hope this helps good luck
