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2 years ago

Determine the value of the force exerted by the surface (normal force) on a

Physics

1 answer:

Advocard [28]2 years ago

8 0

Answer:

53.5 N

Explanation:

Vertical component of the F force 50 sin30 = 25 N upward

force of gravity = m g = 8 * 9.81 =78.5 N Downward

NET downward force by block on table = net upward force exerted by table = 78.5 -25 =53.5 N

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A nylon guitar string is fixed between two lab posts 2.00 m apart. The string has a linear mass density of μ=7.20 g/m\mu=7.20~\t

vladimir2022 [97]

Answer:

4.6 m

Explanation:

First of all, we can find the frequency of the wave in the string with the formula:

$f=\frac{1}{2L}\sqrt{\frac{T}{\mu}}$

where we have

L = 2.00 m is the length of the string

T = 160.00 N is the tension

$\mu =7.20 g/m = 0.0072 kg/m$ is the mass linear density

Solving the equation,

$f=\frac{1}{2(2.00 m)}\sqrt{\frac{160.00 N}{0.0072 kg/m}}=37.3 Hz$

The frequency of the wave in the string is transmitted into the tube, which oscillates resonating at same frequency.

The n=1 mode (fundamental frequency) of an open-open tube is given by

$f=\frac{v}{2L}$

where

v = 343 m/s is the speed of sound

Using f = 37.3 Hz and re-arranging the equation, we find L, the length of the tube:

$L=\frac{v}{2f}=\frac{343 m/s}{2(37.3 Hz)}=4.6 m$

4 0

3 years ago

According to the Big Bang Theory, the density and temperature of the Universe is ___________ now than in the past.

34kurt

Answer:

According to the Big Bang Theory, the density and temperature of the Universe is lower now than in the past.

Hope this answer correct :)

5 0

3 years ago

A photon with a wavelength of 2.29 × 10^–7 meter strikes a mercury atom in the ground state.

4vir4ik [10]

The photon can be absorbed and the energy of the photon is exactly equal to the energy-level difference between the ground state and the level d.

8 0

2 years ago

What is the central core of a atom

MariettaO [177]

Answer:

nucleus is the center of atom

7 0

3 years ago

A basketball player spins the ball with an angular acceleration of 10 rad/s2. What is the ball’s final angular velocity if the b

Lena [83]

Explanation:

It is given that,

The angular acceleration of the basketball, $\alpha=10\ rad/s^2$

Time taken, t = 3 seconds

We need to find the ball’s final angular velocity if the ball starts from rest. It can be calculated using definition of angular acceleration i.e.

$\alpha=\dfrac{\omega_f-\omega_i}{t}$

$\omega_i=0\ (rest)$

$\omega_f=\alpha t$

$\omega_f=10\ rad/s^2\times 3\ s$

$\omega=30\ rad/s$

So, the ball's final angular velocity is 30 rad/s. Hence, this is the required solution.

8 0

2 years ago