Determine the value of the force exerted by the surface (normal force) on a
1 answer:
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Answer:
The correct option is A)
Displacement: 6.71 m, Direction: 63.4 degrees north of east
Explanation:
Given that Dante is leading a parade across the main street in front of city hall.
Let, Initial location of parade is 0i+0j
One block of city is one units on the XY- graph
Statement 1: Parade marches the parade 4 blocks east, then 3 blocks south
New location of parade is 4i-3j
Statement 2: The parade marches 1 block west and 9 blocks north and finally stops.
Final location of parade is (4i-3j)+(-1i+9j)=3i+6j
Displacement is given by
Displacement = (Final destination)-(Initial destination)
Displacement = (3i+6j)-(0i+0j)=3i+6j
Thus,
Magnitude of displacement =
= 6.71 m
Direction of displacement =
=
= 63.43 NE
Therefore, the correct option is A) Displacement: 6.71 m, Direction: 63.4 degrees north of east
Answer: N = Mgcos(theta)
Therefore, the Normal reaction force is equal to Mgcos(theta)
Explanation:
See attached for a sketch.
From the attachment.
.
N = normal reaction force on block
W = weight of the block
theta = angle of the inclined plane to the horizontal
From the sketch, we can see that
N is equal in magnitude but opposite direction to Wy
N = Wy
And
Wy = Wcos(theta)
Wx = Wsin(theta)
Then,
N = Wy = Wcos(theta)
But W = mass × acceleration due to gravity = mg
N = Mgcos(theta)
Therefore, the Normal reaction force is equal to Mgcos(theta)
Answer:
k_max = 31.82 w/mk
k_min = 17.70 w/mk
Explanation:
a) the maximum thermal conductivity is given as
where k_m is thermal conductvitiy of metal
k_p is thermal conductvitiy of carbide
v_m = proportion of metal in the cement = 0.17
v_p = proportion of carbide in the cement = 0.83
= 66*0.17 + 28*0.83
k_max = 31.82 w/mk
b) the minimum thermal conductivity is given as
= \frac{28+66}{28*0.17 +66*0.83}
k_min = 17.70 w/mk