Answer:
The field of view = 66.84°
Explanation:
given:
focal lenght = 15mm
width = 14mm
resolution = 5MP
for us to determine the image size of the square lens of width 14mm
we use Pythagoras theorem,
(diagonal)² = (14)² + (14)²
diagonal = √(392)
the diagonal of the squared camera sensor is the image size in vertical and horizontal.
hence,
image size = √(392) = 19.8mm
Since,
Field of view, fov = 2*arctan(image size/(focal lenght *2))
fov = 2*arctan(19.8/(15 x 2)) = 2*33.425
fov = 66.84°
Answer:
Normal force, 
= 707 N
Given:
Mass of the rider, M = 72.1 kg
acceleration due ti gravity, g = 9.8 m/
Velocity of the elevator is constant
Solution:
Since, the elevator is moving with a constant velocity, therefore, the frame we are dealing with is an inertial frame and will not allow any pseudo force to act on it.
The Normal force, N will now be equal to the weight, W of the body which is the product of its mass and the acceleration acting on the body due to gravity and is given by:
= W = 
putting the values in the above formula
= 
= 707 N (approx)
E/Nucleon = mc^2
Where
m= number of protons*mass of a proton+Number of neutrons*mass of a neutron
For 48Ti, Protons = 22, Neutrons = 26. Protons and Neutrons weigh almost equal at 1.673*10^-27 kg
While 1 amu = 1.661*10^-27 kg
Therefore,
m= {(22+26)*1.673*10^-27}-{47.9359*1.661*10^-27} = 6.8247*10^-28 kg
c= speed of light = 3*10^8 m/s
Then,
Binding energy per nucleon = {6.8247*10^-28*(3*10^8)^2}/48 = 1.28*10^-12 J
