If the small piston has an area of .004 square
1 answer:
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Answer:
The moment of inertia of the motor is 0.0823 Newton-meter-square seconds.
Explanation:
From Newton's Laws of Motion and Principle of Motion of D'Alembert, the net torque of a system (), measured in Newton-meters, is:
(1)
Where:
- Moment of inertia, measured in Newton-meter-square seconds.
- Angular acceleration, measured in radians per square second.
If motor have an uniform acceleration, then we can calculate acceleration by this formula:
(2)
Where:
- Initial angular speed, measured in radians per second.
- Final angular speed, measured in radians per second.
- Time, measured in seconds.
If we know that ,
,
and
, then the moment of inertia of the motor is:
The moment of inertia of the motor is 0.0823 Newton-meter-square seconds.
Answer:
Velocity = 0.309 m/s
Along negative x axis
Explanation:
A pulse moving to the right along the x axis is represented by the wave function
y(x,t) = 2/ (x - 3t)² + 1
At t =0
y(x,0) = 2/ ((x - 3(0))² + 1)
=2 / (x² + 1)
At t = 1
y(x,t) = 2/ ((x - 3(1))² + 1)
= 2 /(( x - 3)² + 1)
At t = 2
y(x,t) = 2/ ((x - 3(2))² + 1)
= 2 /(( x - 6)² + 1)
For the pulse with expression y(x,t) = 4.5²
The Velocity is
V = 2.7 / 8.73
= 0.309 m/s