10x+12/2. Add the x's and the normal numbers and put the equation over 2
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Answer:
63+38=101
Step-by-step explanation:
Answer:
Step-by-step explanation:
Hello!
The variable of interest is
X: mark obtained in an aptitude test by a candidate.
This variable has a mean μ= 128.5 and standard deviation σ= 8.2
You have the data of three scores extracted from the pool of aptitude tests taken.
148, 102, 152
The average is calculated as X[bar]= Σx/n= (148+102+152)/3= 134
An outlier is an observation that is significantly distant from the rest of the data set. They usually represent experimental errors (such as a measurement) or atypical observations. Some statistical measurements, such as the sample mean, are severely affected by this type of values and their presence tends to cause misleading results on a statistical analysis.
Using the mean and the standard deviation, an outlier is any value that is three standard deviations away from the mean: μ±3σ
Using the population values you can calculate the limits that classify an observed value as outlier:
μ±3σ
128.5±3*8.2
(103.9; 153.1)
This means that any value below 103.9 and above 153.1 can be considered an outlier.
For this example, there is only one outlier, that this the extracted score 102
I hope this helps!
<span>answer 1
Nancie is typing is represented by the equation
y = 35x
Therefore, the rate at which Nancie is typing is given by the slope of the straight line that in this case is:
35 words per minute
answer 2
To find the rate at which Suresh is typing we have to find the equation of the line with the data in the table.
For this case, the equation of the line will be given by:
y = 56x
Therefore, the rate at which Suresh is typing is given by the slope of the straight line which in this case is:
56 words per minute
answer 3
Nancie's rate = 35
Suresh's rate = 56
56-35 = 21 words per minute
Nancie's rate is 21words per minute less than Suresh's rate.
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Answer:
configure 3 its B
Step-by-step explanation: