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seraphim [82]
4 years ago
8

Two small fires are spotted by a ranger from a fire tower 60 feet above ground. The angles of depressions re 11.6° and 9.4°. How

far apart are the fires? (The fires are in the same general direction from the tower.)
Mathematics
1 answer:
Hitman42 [59]4 years ago
4 0
<span>The two fires are about 70 feet from each other. The assumption is that the ground is relatively level and that a right triangle will be made with the three points of the triangle being the ranger, the spot on the ground directly beneath the ranger, and the fire itself. So the distance to the first fire will be: Calculate the angle. That will be 90° - 11.6° = 78.4° The distance will be tan(78.4) = X/60 60 tan(78.4) = X 60 * 4.871620136 = X 292.2972082 = X And that's how far the 1st fire is from the ranger's station. Now for the 2nd angle = 90° - 9.4° = 80.6° 60 tan(80.6) = X 60 * 6.040510327 = X 362.4306196 = X And the distance between the two fires will be the difference in distance from the tower, so 362.4306196 - 292.2972082 = 70.13341146 Rounding to 2 significant figures gives 70 feet.</span>
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Answer:

7

Step-by-step explanation:

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5 0
3 years ago
What is the answer using either the substitution method or elimination method
Sophie [7]

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s = 4r - 1

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6r - 20r + 5 = -23

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-14r + 5 = -23

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r = 2

Now that we know that value for the variable r, we can substitute this value into one of our original equations (either one will work, but I am choosing to use the first one):

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8 0
4 years ago
Write the inequality in words.. . 5n – 10 &gt; 26. . Five times n less than ten is twenty-six?
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4 0
4 years ago
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ser-zykov [4K]

Answer:

What is the question?

3 0
3 years ago
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Artyom0805 [142]

Answer:

The classification of the set of circumstances is presented in the following subsections of the understanding.

Step-by-step explanation:

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(a)

Women with whom the mothers have taken DES throughout pregnancy as well as women where its mothers haven't taken DES during pregnancy.

(b)

The information collected seems to have been a sample or survey.  

(c)

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=  \frac{63}{3980}

=  0.015829

Of every thousand women, 15.8 established tissue abnormalities.

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3 years ago
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