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3 years ago

What polyhedron can be formed from a net diagram that had 2 congruent hexagons and 6 congruent rectangles

Mathematics

2 answers:

Sidana [21]3 years ago

4 0

Hello,
an hexagonal right prisme.

DiKsa [7]3 years ago

4 0

Answer:

Hexagonal prism

Step-by-step explanation:

Polyhedron is a three-dimensional figure.

The name of polyhedron with respect to the number sides.

Let's see the name of the polyhedron with respect to the number sides.

cube - which is formed by 6 square faces

Pentagonal prism - which is formed by 2 congruent pentagons and 5 congruent rectangles

Hexagonal prism - which is formed by 2 congruent hexagons and 6 congruent rectangles.

Hexagon is a sided figure.

Therefore, the answer is "Hexagonal prism".

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Compare the values of the underlined digits.

Fantom [35]

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6,300 – the number 3 is in the hundreds place so its value is 300

530 – the number 3 is in the tens place so its value is 30

To answer the question, the value of 3 in 6,300 is 10 times the value of 3 in 530.

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3 years ago

Can someone please help explain this to me I don’t get it and it’s due in a few hours, please

Svet_ta [14]

Explanation:

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3 years ago

The exact value of sec(-60) equals

MaRussiya [10]

This looks hard... good luck ! :D

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3 years ago

Hey please help i’ll give brain

Liono4ka [1.6K]

Answer:

$7 \times 6 = 5 \: sixes + 2 \: sixes \\ 7 \times 6 = 30 + 12 \\ = 42 \\ \\ thank \: you$

5 0

3 years ago

Read 2 more answers

marissa [1.9K]

$\bf \textit{ratios relations for similar figures}
\\\\\\
\begin{array}{cccllll}
side&area&volume\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
\frac{s}{s}=\frac{s}{s}&\frac{s^2}{s^2}=\frac{area}{area}&\frac{s^3}{s^3}=\frac{volume}{volume}
\end{array}\\\\
-----------------------------\\\\
$

$\bf thus
\\\\\\
\begin{array}{llll}
\cfrac{\textit{polygon A}}{\textit{polygon B}}\qquad &\cfrac{24^2}{15^2}=\cfrac{128}{x}
\end{array}$

solve for "x"

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3 years ago