What is the area of the kitchen floor in this floor plan?
2 answers:
Answer: The correct option is (C) 35 sq. meters.
Step-by-step explanation: We are given to find the area of the kitchen floor in the floor plan shown in the figure.
From the figure, we see that
the kitchen is in the form of a rectangle with length 7 meters and breadth 5 meters.
We know that
the area of a rectangle with length l units and breadth b units is given by
For the rectangular kitchen, we have
length, l = 7 meters
and
breadth, b = 5 meters.
Therefore, the area of the kitchen floor in the floor plan is given by
Thus, option (C) is CORRECT.
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Let r = (t,t^2,t^3)
Then r' = (1, 2t, 3t^2)
General Line integral is:
The limits are 0 to 1
f(r) = 2x + 9z = 2t +9t^3
|r'| is magnitude of derivative vector
Fortunately, this simplifies nicely with a 'u' substitution.
Let u = 1+4t^2 +9t^4
du = 8t + 36t^3 dt
After integrating using power rule, replace 'u' with function for 't' and evaluate limits:
Then r' = (1, 2t, 3t^2)
General Line integral is:
The limits are 0 to 1
f(r) = 2x + 9z = 2t +9t^3
|r'| is magnitude of derivative vector
Fortunately, this simplifies nicely with a 'u' substitution.
Let u = 1+4t^2 +9t^4
du = 8t + 36t^3 dt
After integrating using power rule, replace 'u' with function for 't' and evaluate limits: