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Vesnalui [34]
2 years ago
6

What is the area of the kitchen floor in this floor plan?

Mathematics
2 answers:
slava [35]2 years ago
8 0
First you would figure out the dimensions, which are 7 ft by 5 ft. Then, multiply those together, which equals 35 sq ft. The answer to your question is C - 35 sq ft. Hope this helps!
RUDIKE [14]2 years ago
6 0

Answer:  The correct option is (C) 35 sq. meters.

Step-by-step explanation:  We are given to find the area of the kitchen floor in the floor plan shown in the figure.

From the figure, we see that

the kitchen is in the form of a rectangle with length 7 meters and breadth 5 meters.

We know that

the area of a rectangle with length l units and breadth b units is given by

A=l\times b.

For the rectangular kitchen, we have

length, l = 7 meters

and

breadth, b = 5 meters.

Therefore, the area of the kitchen floor in the floor plan is given by

A=l\times b=7\times 5=35~\textup{sq. meters}.

Thus, option (C) is CORRECT.

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Orlov [11]

Answer:

3rd option

Step-by-step explanation:

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5 0
2 years ago
Given that cot θ = 1/√5, what is the value of (sec²θ - cosec²θ)/(sec²θ + cosec²θ) ?
Bogdan [553]

Step-by-step explanation:

\mathsf{Given :\;\dfrac{{sec}^2\theta - co{sec}^2\theta}{{sec}^2\theta + co{sec}^2\theta}}

\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{{sec}\theta = \dfrac{1}{cos\theta}}}}

\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{co{sec}\theta = \dfrac{1}{sin\theta}}}}

\mathsf{\implies \dfrac{\dfrac{1}{cos^2\theta} - \dfrac{1}{sin^2\theta}}{\dfrac{1}{cos^2\theta} + \dfrac{1}{sin^2\theta}}}

\mathsf{\implies \dfrac{\dfrac{sin^2\theta - cos^2\theta}{sin^2\theta.cos^2\theta}}{\dfrac{sin^2\theta + cos^2\theta}{sin^2\theta.cos^2\theta}}}

\mathsf{\implies \dfrac{sin^2\theta - cos^2\theta}{sin^2\theta + cos^2\theta}}

Taking sin²θ common in both numerator & denominator, We get :

\mathsf{\implies \dfrac{sin^2\theta\left(1 - \dfrac{cos^2\theta}{sin^2\theta}\right)}{sin^2\theta\left(1 + \dfrac{cos^2\theta}{sin^2\theta}\right)}}

\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{cot\theta = \dfrac{cos\theta}{sin\theta}}}}

\mathsf{\implies \dfrac{1 -cot^2\theta}{1 + cot^2\theta}}

\mathsf{Given :\;cot\theta = \dfrac{1}{\sqrt{5}}}

\mathsf{\implies \dfrac{1 - \left(\dfrac{1}{\sqrt{5}}\right)^2}{1 + \left(\dfrac{1}{\sqrt{5}}\right)^2}}

\mathsf{\implies \dfrac{1 - \dfrac{1}{5}}{1 + \dfrac{1}{5}}}

\mathsf{\implies \dfrac{\dfrac{5 - 1}{5}}{\dfrac{5 + 1}{5}}}

\mathsf{\implies \dfrac{5 - 1}{5 + 1}}

\mathsf{\implies \dfrac{4}{6}}

\mathsf{\implies \dfrac{2}{3}}

<u>Hence</u><u>,</u><u> option</u><u> </u><u>(</u><u>a)</u><u> </u><u>2</u><u>/</u><u>3</u><u> </u><u>is </u><u>your</u><u> </u><u>correct</u><u> </u><u>answer</u><u>.</u>

3 0
2 years ago
What is the value of x?
grandymaker [24]

i got 5.14cm i don´t know how much you are supposed to round though

36/42= 0.857142857 x 6=5.142857143

6 0
3 years ago
PLSSS HELP AND EXPLAIN :)
vodka [1.7K]

Answer:

968

Step-by-step explanation:

Rectangular Prism: 11*11*5 = 605

Square Pyramid: 11*11 * 9 over 3 = 363

363+605= 968

3 0
2 years ago
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